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3 years ago

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Determine which of the following are functions. Select all that apply. A 2-column table with 5 rows. Column 1 is labeled x with

entries negative 6, negative 2, 2, 6, 10. Column 2 is labeled y with entries 17, 13, 9, 5, 1. {(-4, 2), (-2, 1), (-1, 3) (-1, 4), (0, 5), (2, 5)} A 2-column table with 5 rows. Column 1 is labeled x with entries negative 3, 0, 0, 3, 4. Column 2 is labeled y with entries 4, 2, 4, 8, 7. y = -4x² + 45x + 9

2 answers:

iragen [17]3 years ago

8 0

Answer:

Step-by-step explanation:

no.

tangare [24]3 years ago

8 0

The answer is A and D

May I please get brainliest? :)

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What function is shown in the graph above?

Verizon [17]

By definition of <em>linear</em> functions and the comparison with the attached figure, the function that represents the graph is y = (7/15) · x + 4, - 6 ≤ x ≤ 9.

<h3>What kind of function represents the graph?</h3>

Graphically speaking, <em>linear</em> functions represent lines and we see that the line seen in the figure presents two bounds, the points (- 6, 0) and (9, 7). <em>Linear</em> functions are characterized by slope and intercept:

y = m · x + b (1)

Slope

m = (7 - 0)/[9 - (- 6)]

m = 7/15

Intercept

b = 4

By definition of <em>linear</em> functions and the comparison with the attached figure, the function that represents the graph is y = (7/15) · x + 4, - 6 ≤ x ≤ 9.

To learn more on linear functions: brainly.com/question/14695009

#SPJ1

8 0

2 years ago

ASAP please it’s very important

zaharov [31]

Answer:

x = 30° and 330°

Step-by-step explanation:

Assuming the intervals is {0 , 2π} or {0° , 360°}

$tan\ x=\frac{-\sqrt{3} }{3} \\\\x=tan^{-1} (\frac{-\sqrt{3} }{3})\\\\x = -30$

So it means it lies in the 2nd and 4th quadrant because tangent is negative in the 2nd and 4th quadrant

so the two solutions are

x = 30° and 330° or

$x=\frac{\pi }{6}\ radians\ \ , \ \ \frac{11\pi }{6}\ radians$

4 0

3 years ago

An elevator can hold a maximum of 1500 pounds. An average child weighs 75 pounds and the average adult weighs 150 pounds. The el

CaHeK987 [17]

<u>Let's take this problem step-by-step</u>:

<u>Let's first set up some variables</u>:

c: # of children
a: # of adults

<u>Let's examine the information given:</u>

Elevator can hold a maximum of 1500 pounds

⇒ average child is 75 pounds

⇒ average adult is 150 pounds

⇒<em> therefore</em>: $75c + 150a\leq 1500$

Elevator can fit no more than 14 people

⇒ <em>therefore</em>: $c + a \leq 14$

<u>Let's graph the equations</u>:

$75c+150a\leq 1500\\c+a\leq 14$

⇒ look at the image attached

<u>The point at which the two graphs intersect:</u>

⇒ <em>is the solution that represents the amount of children and adults and </em>

<em> their combine weight</em>

<em />

<u><em>With the horizontal axis being the # of children and vertical axis being the # of adults</em></u><em>:</em>

<em> ⇒ the </em><em>solution is 8 children and 6 adults</em>

<em></em>

<u>Answer: 8 children and 6 adults</u>

<u></u>

Hope that helped!

<em />

7 0

2 years ago

Two roots of a 3 degree polynomial equation are 5 and-5

notka56 [123]

Hello,

I suppose you want the equation

There are 2 infinite solutions:
y=k(x-5)²(x+5)
or
y=k(x-5)(x+5)²

3 0

3 years ago

PLEASE HELP WILL MARK BRAINLIEST!!(plz show work too)

trapecia [35]

$\huge \bf༆ Answer ༄$

Let the capacity of bus be x students

And van be y students, now ;

From the given statements we get two equations ~

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:2x + 10y = 260 \: \: \: \: \: (1)$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:13x + 5y = 670 \: \: \: \: \: (2)$

multiply the equation (2) with 2 [ it won't change the values ]

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:2x + 10y = 260 \: \: \: \: \: \: \: \: \: (1)$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:26x + 10y = 1340 \: \: \: \: \: (3)$

Now, deduct equation (1) from equation (3)

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:26x + 10y - 2x - 10y = 1340 - 260$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:24x = 1080$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:x = 1080 \div 24$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:x = 45$

Therefore each bus can carry (x) = 45 students

Now, plug the value of x in equation (1) to find y ~

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:2x + 10y = 260$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:(2 \times 45) + 10y = 260$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:90 + 10y = 260$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:10y = 260 - 90$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:10y = 170$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:y = 170 \div 10$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:y = 17$

Hence, each van can carry (y) = 17 students in total.

5 0

3 years ago