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8_murik_8 [283]
3 years ago
12

((a^-1)/ (b^-1) square root a)

Mathematics
2 answers:
Leya [2.2K]3 years ago
5 0

Answer:

\rightarrow \frac{a^{-1}}{b^{-1}\times \sqrt{a}}\\\\\rightarrow \frac{a^{-1}}{b^{-1}\times a^{\frac{1}{2}}}\\\\\rightarrow a^{-1-\frac{1}{2}} \times b^1\\\\=a^{\frac{-3}{2}} \times b\\\\\rightarrow ca^pb^q=a^{\frac{-3}{2}} \times b\\\\c=1\\\\p=\frac{-3}{2}\\\\q=1

kari74 [83]3 years ago
3 0
So the problem ask to calculate and covert the said equation or expression to the form of ca^pb^q where as all of the variables is a number. So base in that information and following some formula, the answer would be a^(-3/2)b. I hope you are satisfied with my answer 
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Chords AC and DB intersect at point E. Find the value of x.
Elina [12.6K]

Answer:

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4 0
3 years ago
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Mars2501 [29]

Answer:

5x^2 +8x-4

Step-by-step explanation:

(5x - 2) * (x  + 2)

We can FOIL

first: 5x*x = 5x^2

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inner: -2x

last : -2*2 = -4

Add these together

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3 years ago
A curious patterns occurs in a group of people who all shake hands with one another. It turns out that you can predict the numbe
ycow [4]

Missing part of the question

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Answer:

S_n = \frac{n}{2}(n - 1)

Step-by-step explanation:

Given

For 5 people

\begin{array}{cc}{People} & {Handshakes} & {5} & {4} & {4} & {3} & {3} & {2} & {2} & {1} & {1} & {0} &{Total} & {10} \ \end{array}

Using the given instance of 5 people, the number of handshakes can be represented as:

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The above sequence is an arithmetic sequence and the total number of handshakes is the sum of n terms of the sequence.

S_n = \frac{n}{2}{(T_1 + T_n})

Where

T_1 = n - 1 --- The first term

T_n = 0 --- The last term

So:

S_n = \frac{n}{2}(n - 1 + 0)

S_n = \frac{n}{2}(n - 1)

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2 years ago
What is the amplitude of the graph of
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It is 2 :)
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Would appreciate brainliest answer :)
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2 years ago
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g100num [7]

Answer:

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Step-by-step explanation:

8 × 2 = 16 adding 1 = 17

3 0
3 years ago
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