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yKpoI14uk [10]
3 years ago
15

Help me with this question

Mathematics
1 answer:
NARA [144]3 years ago
6 0
Point-slope form is (3-0)/(-2-3)= -3/5 slop-intercept form is y= -3x+9
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PLEASE HELP ME GUYS OR I WONT PASS <br>this calculus!!!!​
KonstantinChe [14]

Answer:

b.  \displaystyle \frac{1}{2}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Functions
  • Function Notation
  • Exponential Rule [Rewrite]:                                                                              \displaystyle b^{-m} = \frac{1}{b^m}
  • Exponential Rule [Root Rewrite]:                                                                     \displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}<u> </u>

<u>Calculus</u>

Derivatives

Derivative Notation

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                       \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

<em />\displaystyle H(x) = \sqrt[3]{F(x)}<em />

<em />

<u>Step 2: Differentiate</u>

  1. Rewrite function [Exponential Rule - Root Rewrite]:                                      \displaystyle H(x) = [F(x)]^\bigg{\frac{1}{3}}
  2. Chain Rule:                                                                                                        \displaystyle H'(x) = \frac{d}{dx} \bigg[ [F(x)]^\bigg{\frac{1}{3}} \bigg] \cdot \frac{d}{dx}[F(x)]
  3. Basic Power Rule:                                                                                             \displaystyle H'(x) = \frac{1}{3}[F(x)]^\bigg{\frac{1}{3} - 1} \cdot F'(x)
  4. Simplify:                                                                                                             \displaystyle H'(x) = \frac{F'(x)}{3}[F(x)]^\bigg{\frac{-2}{3}}
  5. Rewrite [Exponential Rule - Rewrite]:                                                              \displaystyle H'(x) = \frac{F'(x)}{3[F(x)]^\bigg{\frac{2}{3}}}

<u>Step 3: Evaluate</u>

  1. Substitute in <em>x</em> [Derivative]:                                                                              \displaystyle H'(5) = \frac{F'(5)}{3[F(5)]^\bigg{\frac{2}{3}}}
  2. Substitute in function values:                                                                          \displaystyle H'(5) = \frac{6}{3(8)^\bigg{\frac{2}{3}}}
  3. Exponents:                                                                                                        \displaystyle H'(5) = \frac{6}{3(4)}
  4. Multiply:                                                                                                             \displaystyle H'(5) = \frac{6}{12}
  5. Simplify:                                                                                                             \displaystyle H'(5) = \frac{1}{2}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Derivatives

Book: College Calculus 10e

5 0
3 years ago
Add (4x^2-xy-y^2) and (x^2+5xy+8y^2) simplify your answer:
bazaltina [42]

Answer:

To find a, b, and c, rewrite in the standard form ax2+bx+c=0ax2+bx+c=0.

a=1, b=3, c=0

8 0
3 years ago
Read 2 more answers
Does the numerator impact whether a fraction will have a finite or infinite decimal?
Misha Larkins [42]

Answer:DECIDING IF A FRACTION IS A FINITE OR INFINITE REPEATING DECIMAL ... Need a short break? RATIONAL and IRRATIONAL NUMBERS. The rational numbers are numbers that can be written in the form ab a b , ... start by putting the fraction in simplest form;; then, factor the denominator into primes.

Step-by-step explanation:

6 0
4 years ago
(b) factorise <br>(3m-1)(6-a)-(m+3)(6-a)​
Step2247 [10]

Answer:

Step-by-step explanation:

(3m-1)(6-a)-(m+3)(6-a)

=3m(6-a)-1(6-a)-m(6-a)+3(6-a)

=18m-3ma-6+a-6m+ma+18-3a

=12m-2ma+12-2a

=2(6m-ma+6-a)

7 0
3 years ago
Use the factorization to find the values of x for which p(x) = 0. (x – 1)(x 1)(x 5) = 0 x – 1 = 0, so x = x 1 = 0, so x = x 5 =
Sladkaya [172]

Answer: (x – 1)(x + 1)(x + 5) = 0

x – 1 = 0, so x =  1

x + 1 = 0, so x =  -1

x + 5 = 0, so x = -5

3 0
2 years ago
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