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Fofino [41]
3 years ago
8

Simplify the expression 5 + 2 ⋅ {(2 + 5) ⋅ 5 + 5] 1: 55 2: 85 3: 105 4: 115

Mathematics
2 answers:
FromTheMoon [43]3 years ago
6 0

Answer:

85

Step-by-step explanation:

Order of operations rules (PEMDAS) govern here.  Anything inside parentheses must be done first, followed by exponentiation, mult. and div., and add. and subtr. last.

Add 2+5 first:    5 + 2*{(7)*5 + 5}

Perform the work shown inside the brackets {  and  }:  5 + 2*{40}

Perform the indicated mult.:  5 + 80

Finally, add:  85


g100num [7]3 years ago
6 0
<h2><u><em>Answer:its 858 because 125 plus 125 plus 125 plus 125=858 and thats ur answer simple math boi</em></u> <em><u>so go to school</u></em></h2>

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3 years ago
What is one solution of 5x-13<br>​
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Step-by-step explanation:

5x-13 = 12

    +13   +13

------------------------

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3 years ago
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\bf \textit{Periodic Exponential Decay}\\\\&#10;A=I(1 - r)^{\frac{t}{p}}\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\to &1013\\&#10;I=\textit{initial amount}\\&#10;r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\&#10;t=\textit{meters climbed}\to &0\\&#10;p=period\to &1000&#10;\end{cases}&#10;\\\\\\&#10;1013=I(1-0.118)^{\frac{0}{1000}}\implies 1013=I\cdot 1\implies 1013=I

so, the inital amount is 1013, when t = 0,

\bf \textit{Periodic Exponential Decay}\\\\&#10;A=I(1- r)^{\frac{t}{p}}\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;I=\textit{initial amount}\to &1013\\&#10;r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\&#10;t=\textit{meters climbed}\to &t\\&#10;p=period\to &1000&#10;\end{cases}&#10;\\\\\\&#10;A=1013(1-0.118)^{\frac{t}{1000}}\implies A=1013(0.882)^{\frac{t}{1000}}

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7 0
3 years ago
A student is using the completing the square method to transform the equation x2-10x+ 36 = 0 to the form (x-h) 2+k = 0. which st
andreev551 [17]
Obviously the Correct Step would give him the correct answer lol !

But, here he goes !!

( {x}^{2}  - 10x + 36)

= ( {x}^{2}  - 2(x)(5) +  {(5)}^{2} ) + 11

= (x - 5)^{2}  + 11

✓ So, h = 5 ; k = 11 would make him correct
4 0
4 years ago
Physicists estimate that there are between 10^78 and 10^82 atoms in the universe. How do these two numbers compare with one anot
Ann [662]

Answer:

These two values show the range of maximum and the minimum possible approximation of the amount of atoms in the universe.

10000 of the small universe will fit into the big universe.

Step-by-step explanation:

These values are a representative of the possible number of atoms in the universe. They both give a range of possible numbers, within which the number of atoms in the universe can be assigned a a particular value. The range is used to indicate that the value cannot be be exactly determined to be a particular exact number.

The two numbers given are

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If the the larger number of 10^82 is correct, we'll have

10^82 ÷ 10^78

==> 10^(82 -78) = 10000 of the small universe will fit into the larger universe.

4 0
3 years ago
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