Probability that 2 of the 10 chargers will be defective =0.35
Number of ways of selecting 10 chargers from 20 chargers is 20C10
20C10 = 184756
Number of ways of selecting 10 chargers from 20 = 184756
Number of ways of selecting 2 defective chargers from 5 defective chargers = 5C2
5C2 = 10
Since 2 defective chargers have been chosen, there remains 8 to choose
Number of ways of selecting 8 good chargers from 15 remaining chargers = 15C8
Number of ways of selecting 8 good chargers from 15 remaining chargers = 6435
Probability that 2 of the 10 will be defective =
(10x6435)/184756
Probability that 2 of the 10 will be defective = 64350/184756
Probability that 2 of the 10 chargers will be defective =0.35
Learn more on probability here: brainly.com/question/24756209
Answer:
2.9 years
Step-by-step explanation:
Let x be larger integer so x-3 is the smaller
so x^2+ x-3 = 87
x^2 +x -90=0 and factor
(x-9)(x+10)=0
x=9 or x=-10 but x must be positive
so x=9 and smaller number is 6
Answer: a. 0.40 b. 0.23 c . 0.435 d . 0.25
Step-by-step explanation:
melanin content Total
high low
moisture high 13 10 23
content low 47 30 77
Total 60 40 <u> </u><u>100</u>
Let A denote the event that a sample has low melanin content, and let B denote the event that a sample has high moisture content.
a) Total skin samples has low melanin content = 10+30=40
P(A)=
b) Total skin samples has high moisture content = 13+10=23
P(B) =
c) A ∩ B = Total skin samples has both low melanin content and high moisture content =10
P(A ∩ B) =
Using conditional probability formula , 
d) 
