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Marat540 [252]
2 years ago
12

Evaluate the expression. Drag the answer into the box to match the expression.

Mathematics
2 answers:
Lelu [443]2 years ago
5 0

27.((3^{3})^{-1}  = 27.(27)^{-1} = 27 .\frac{1}{27} = 1

This is because 3^{3} = 3 x 3 x 3 = 9 x 3 = 27

And (27)^{-1}  means  \frac{1}{27}

For this reason, 27. (27)^{-1} = 1

Positive indices mean we have to multiply the same number twice or thrice based on the value of the index. On the other hand, negative indices mean we have to divide by the same number twice or thrice based on the value of the index.

NeTakaya2 years ago
3 0

Answer:

27.((3^{3})^{-1}  = 27.(27)^{-1} = 27 .\frac{1}{27} = 1

Step-by-step explanation:

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If AC = x + 5 and AB = 3x - 1... what is the length of BC?
Hatshy [7]
If B is the midpoint of AC, then |AB| = |AC|.
|AB| = 3x + 2
|BC| = 5x - 10
Therefore we have the equation:
3x + 2 = 5x - 10     |subtract 2 from both sides
3x = 5x - 12      |subtract 5x from both sides
-2x = -12      |divide both sides by (-2)
x = 6

Read more on Brainly.com - brainly.com/question/11324096#readmore
4 0
3 years ago
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by th
irga5000 [103]

Answer:

The rocket hits the ground at a time of 11.59 seconds.

Step-by-step explanation:

The height of the rocket, after x seconds, is given by the following equation:

y = -16x^2 + 177x + 98

It hits the ground when y = 0, so we have to find x for which y = 0, which is a quadratic equation.

Finding the roots of a quadratic equation:

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = a(x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

In this question:

y = -16x^2 + 177x + 98

-16x^2 + 177x + 98 = 0

So

a = -16, b = 177, c = 98

\bigtriangleup = 177^{2} - 4(-16)(98) = 37601

x_{1} = \frac{-177 + \sqrt{37601}}{2*(-16)} = -0.53

x_{2} = \frac{-177 - \sqrt{37601}}{2*(-16)} = 11.59

Since time is a positive measure, the rocket hits the ground at a time of 11.59 seconds.

4 0
3 years ago
HURRY TImed Which of the following is equivalent to 3 1/3? A 1/27 B 1 C 3√3 D 1log33
Allisa [31]

Answer:

Step-by-step explanation:

3 1/3 is a mixed number, and is equivalent to 10/3.

4 0
3 years ago
A professor gives her 100 students an exam; scores are normally distributed. The section has an average exam score of 80 with a
frozen [14]

Answer:

6.18% of the class has an exam score of A- or higher.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 80, \sigma = 6.5

What percentage of the class has an exam score of A- or higher (defined as at least 90)?

This is 1 subtracted by the pvalue of Z when X = 90. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{90 - 80}{6.5}

Z = 1.54

Z = 1.54 has a pvalue of 0.9382

1 - 0.9382 = 0.0618

6.18% of the class has an exam score of A- or higher.

4 0
2 years ago
What is the 32nd term of the arithmetic sequence where a1 = –33 and a9 = –121?
Aleksandr-060686 [28]
a_1=-33;\ a_9=-121\\\\a_9-a_1=8d\\\\8d=-121-(-33)\\8d=-121+33\\8d=-88\ \ \ \ |divide\ both\ sides\ by\ 8\\d=-11\\\\a_{32}=a_1+31d\\\\a_{32}=-33+31\cdot(-11)=-33-341=-374\\\\Answer:\boxed{a_{32}=-374}
8 0
3 years ago
Read 2 more answers
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