<h3>
Answer: </h3><h3>
speed of train A = 44 mph</h3>
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Work Shown:
x = speed of train A
y = speed of train B
"train A travels 4/5 the speed of train B" (I'm assuming "train one" is supposed to read "train B"). So this means x = (4/5)y
distance = rate*time
d = x*7
d = (4/5)y*7 = (28/5)y represents the distance train A travels
d = y*7 = 7y represents the distance train B travels
summing those distances will give us 693
(28/5)y + 7y = 693
5*( (28/5)y + 7y ) = 5*693
28y + 35y = 3465
63y = 3465
y = 3465/63
y = 55
Train B's speed is 55 mph
4/5 of that is (4/5)y = (4/5)*55 = 4*11 = 44 mph
Train A's speed is 44 mph
Answer:
2 is the required answer.
Step-by-step explanation:
<u>Solution:</u>
<u>Given</u><u>:</u>
-5x+3y=2..............(i)
Putting the value of y=2x in the equation (i); we get:
i.e -5x+3×2x=2
or, -5x+6x=2
or, x=2
i.e. x=2
y=2x=2×2=4
The percent of people of smoke cigarettes is 20.9%..
Answer:
Yes by SSS because you have the same hypotenuse and same hatch marks on other sides
Answer:
<h2>
12h</h2>
Step-by-step explanation:
each term has h^1
each term's coefficient is divisible by 12
12h( 3, h^5, 4h^4)
<h2>
So, the GCF is 12h </h2>
