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Serjik [45]
3 years ago
5

(6x to 2nd power -3x -7) (2x +5)

Mathematics
1 answer:
tigry1 [53]3 years ago
4 0
(6x² - 3x - 7)(2x + 5)
12x³ + 30x² - 6x² - 15x - 14x - 35
12x³ + 24x² - 29x - 35
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In triangle ABC, m∠A=55 triangle ABC, m∠A=55°, c=11c=11, and m∠B=19m∠B=19°. Find the perimeter of the triangle
Ainat [17]
First, we illustrate the problem as shown in the picture. By convention, we denote capital letters as angles and the small letters as opposite sides to those respective angles. We can find the perimeter of the triangle by adding all it sides. So, the next step is to find sides a and b.

Since a triangle has a total of 180° in interior angles, then angle C can be solved by

180° = A + B + C
C = 180° - 55° - 19°
C = 106°

Next, we use the Law of Sines. This law can be used in any type of triangle. This law states that there is a fixed ratio of side to sine of the opposite angle. In equation, that would be written as

a/sin A = b/sin B = c/sin C

Since, we know already side c and angle C, the fixed ratio is then,

11/sin 106° = 11.443

The last step is to apply ratio and proportion:

11.433 = a/sin 55°
a = 9.37 units

11.433 = b/sin 19°
b = 3.73 units

Thus, the perimeter of the triangle is 
P = a + b + c
P = 9.37 +3.73 +11
P = 24.1 units

5 0
3 years ago
Please help !!!!!!!!!!!
DochEvi [55]
Forgive if I'm wrong but I think the answer is D).5.
4 0
4 years ago
A car driving at 20m/s accelerates at 3m/s2 for 3s. What is its final velocity? How far will it travel during this time?
-BARSIC- [3]

Answers:

Final velocity = 29 m/s

Distance traveled = 73.5 meters

========================================================

Work Shown:

The given data is

v_i = 20 \text{ m}/\text{s} = \text{initial velocity}\\\\a = 3 \text{ m}/\text{s}^2 = \text{acceleration}\\\\t = 3 \text{ s} = \text{time duration}\\\\

This leads to

v_f = v_i + a*t\\\\v_f = 20 + 3*3\\\\v_f = 20 + 9\\\\v_f = 29\\\\

The final velocity is 29 m/s.

----------

We can use that final velocity to find the distance traveled.

x = 0.5*(v_i+v_f)*t\\\\x = 0.5*(20+29)*3\\\\x = 0.5*(49)*3\\\\x = 24.5*3\\\\x = 73.5\\\\

The distance traveled is 73.5 meters.

----------

An alternative way to calculate the distance is to do this

x = \frac{(v_f)^2 - (v_i)^2}{2a}\\\\x = \frac{(29)^2 - (20)^2}{2*3}\\\\x = \frac{841 - 400}{6}\\\\x = \frac{441}{6}\\\\x = 73.5\\\\

Or you could do this

x = v_i*t + 0.5*a*t^2\\\\x = 20*3 + 0.5*3*3^2\\\\x = 20*3 + 0.5*3*9\\\\x = 60 + 13.5\\\\x = 73.5\\\\

For more information, check out the Kinematics equations.

7 0
2 years ago
A class 4 truck weighs between 14,000 and 16,000. What is the weight range in tons?
Evgen [1.6K]
A ton is 2000 pounds. so it would be between 7 and 8 tons
8 0
3 years ago
Mattias gets dressed in the dark one morning and chooses his clothes at random. He chooses a shirt (green, red, or yellow), a pa
Oliga [24]

Answer:

So, the number of ways in which the dress can be chosen

= 3 × 2 × 2

= 12.

And the combinations are

(Green shirt, black pant, checkered shoes),

(Green shirt, black pant, red shoes),

(Green shirt, blue pant, checkered shoes),

(Green shirt, blue pant, red shoes),

(Red shirt, black pant, checkered shoes),

(Red shirt, black pant, red shoes),

(Red shirt, blue pant, checkered shoes),

(Red shirt, blue pant, red shoes),

(Yellow shirt, black pant, checkered shoes),

(Yellow shirt, black pant, red shoes),

(Yellow shirt, blue pant, checkered shoes),

(Yellow shirt, blue pant, red shoes).

The tree diagram is below.

Step-by-step explanation:

7 0
3 years ago
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