The two dot plots below compare the forearm lengths of two groups of schoolchildren:
1 answer:
Answer:
The correct option is B.
Step-by-step explanation:
From the given dot plot we can say that 3 children have 9 in. long forearm, 4 children have 10 in. long forearm and 3 children have 11 in. long forearm.
The average of length of forearms of Group A is
The average of length of forearms of Group A is 10 inches.
From the given dot plot we can say that 3 children have 10 in. long forearm, 5 children have 11 in. long forearm and 2 children have 12 in. long forearm.
The average of length of forearms of Group B is
The average of length of forearms of Group B is 10.9 inches.
10.9>10 it means Group B has longer average forearm length. It is true because two children have a forearm length longer than 11 inches.
Therefore the correct option is B.
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Answer: The empty set { } which can be represented by the symbol 
Why is this the answer? Because there is nothing inside set M. Set M is itself the empty set. Intersecting the empty set with any other set leads to the empty set again.
Why is this the answer? Because there is nothing inside set M. Set M is itself the empty set. Intersecting the empty set with any other set leads to the empty set again.
1d) ↑ (Do the same but turned if that's easier)
1a) 199
1b) 193
1c) 217
1e) Based on the box plot, we can for example, find the lowest and greatest values, the range (largest - smallest), the mean (all values / # values), and the median middle value or q2 given by the second line in the box.
2b) 7
2c) 9.5
2d) ↑
2e) because the data is not ordered, it is difficult to determine the quartile data. Once it is ordered like 6, 7, 7, 7, 8, 8, 9, 10, 10. The data can be visualized alot easier. With the box plot we can determine q3 of the data by looking at the 3rd line, using the whiskers of the box to find the minimum and maximum values.
3)
You need to find the minimum, maximum, the quartile data obtained by having an even amount of data on both sides, order it so that values can be grouped. this includes q1, q2 (or median), and q3.
In this case the ordered data would be: 4,6,8,8,9,11,12,14,14,16.
[4, 6, 8, 8, 9] [] [11, 12, 14, 14, 16]
4 is the minimum, 16 is the maximum, q1 is 8, q3 is 14, and median is 10.
4) ↑
5)
You need to find the minimum, maximum, the quartile data obtained by having an even amount of data on both sides, order it so that values can be grouped. this includes q1, q2 (or median), and q3.
In this case the ordered data would be:
45, 45, 50, 55, 60, 70, 70, 75, 80, 85
[45, 45, 50, 55, 60] [] [70, 70, 75, 80, 85]
45 is the minimum, 85 is the maximum, q1 is 50, q3 is 75, and median is 65.
6) ↑
