The two dot plots below compare the forearm lengths of two groups of schoolchildren:
1 answer:
Answer:
The correct option is B.
Step-by-step explanation:
From the given dot plot we can say that 3 children have 9 in. long forearm, 4 children have 10 in. long forearm and 3 children have 11 in. long forearm.
The average of length of forearms of Group A is
The average of length of forearms of Group A is 10 inches.
From the given dot plot we can say that 3 children have 10 in. long forearm, 5 children have 11 in. long forearm and 2 children have 12 in. long forearm.
The average of length of forearms of Group B is
The average of length of forearms of Group B is 10.9 inches.
10.9>10 it means Group B has longer average forearm length. It is true because two children have a forearm length longer than 11 inches.
Therefore the correct option is B.
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Answer:
1). x = 81
2). x = 84
Step-by-step explanation:
1). By applying geometric mean theorem in the given triangle,
56x = (18√14)²
56x = 4536
x =
x = 81
2). By applying geometric mean theorem,
16x = (8√21)²
16x = 1344
x =
x = 84