<span>Another answer:
According to the figure, the coordinates of JKLM are, J(-7,-2), K(-4,-2), L(-2,-5) and M(-9,-5)
JKLM is translated to J'K'L'M' by means of the rule (x+8, y-3), we should know that (x, y) are coordinates of the pre image, to find the coordinates of each image we have (x', y') such that
x' =x+8, and y' =y-3. Therefore, the coordinates of L' can be found by L'(-2+8, -5-3)=(6, -8)
the final answer is L'(6, -8).</span>
Answer
0.5454...
Step-by-step explanation:
0.5454
11⟌60000
<u> - 0</u>
60
<u>- 55</u>
50
<u>- 44</u>
60
<u>- 55</u>
50
<u>- 44</u>
6
Use distance formula d=sqrt root (y2-y1)^2+(x2-x1)^2. So (-3, 4) and (1, 7). D= sqrt root ( 7-4)^2+(-3+1)^2. So now solve d= sqrt (3)^2+(-2)^2. Now d= sqrt 9+4. D= sqrt 13 or 3.60555
17-8 because they both have just 1 added to them
