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Zigmanuir [339]
3 years ago
9

I need help finding this

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
4 0
The graph for y=f(x) is given in the picture.

You have to find the value of the function f(x) at x=-2.

From the graph, at x = -2, value of y = 2.

Thus, the value of function is:

\boxed{\textbf{ \red {y = f(-2) = 2}}}
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A theater group made appearances in two cities. The hotel charge before tax in the second city was $500 lower than in the first.
Mazyrski [523]

Answer:

First city: $5,500

Second city: $5,000

Step-by-step explanation:

Let's define x as the hotel price in the first city and y the hotel price in the second city.  We can start with this equation:

y = x - 500 (The hotel before tax in the 2nd city was $500 lower than in the 1st.)

Then we can say

0.065x + 0.045y = 582.50  (the sum of the tax amounts were $582.50)

We place the value of y from the first equation in the second equation:

0.065x + 0.045 (x - 500) = 582.50

0.065x + 0.045x - 22.50 = 582.50 (simplifying and adding 22.5 on each side)...

0.11x = 605

x = 5,500

The cost of the first hotel was $5,500

Thus, the cost of the second hotel was $5,000 (x - 500)

6 0
3 years ago
Solve the equation 3(x-3)=6x+3
AnnZ [28]

why is no one answering  I have the same question  

3 0
3 years ago
Read 2 more answers
What is the expression using factorials. 45
3241004551 [841]
10! / (!2 * 8!) = '10 choose 10 choose 8 
3 0
4 years ago
Solve the triangle. Round side measure to the nearest tenth and angle measures to the nearest degree.
shutvik [7]
First calculate the missing angle \alpha. By knowing all angles in triangle have a sum of 180°.

\alpha=180-(\gamma+\beta)
\alpha=180-(90+49)=\boxed{41}

Now we required to use angle functions in a right triangle. The cosine of \beta is equal to the relation of side a and hypotenuse c.

Now we solve this for hypotenuse.

\cos(\beta)=\frac{a}{c}

c=\frac{a}{\cos(\beta)}

Now put in the numbers.

c=\frac{9}{\cos(49)}\approx\boxed{13.7}

So we know the length of hypotenuse and length of side a therefore side b can be calculated using Pythagorean theorem: c^2=a^2+b^2.

Solve for side b.

c^2=a^2+b^2

b=\sqrt{c^2-a^2}

b=\sqrt{13.7^2-9^2}\approx\boxed{9.7}

So there you go. If you have any questions feel free to ask.

r3t40
6 0
4 years ago
I need some help with my lesson pleaseee
andrezito [222]
It is the second choice
5 0
4 years ago
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