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3 years ago

I need help finding this

Mathematics

1 answer:

SCORPION-xisa [38]3 years ago

4 0

The graph for y=f(x) is given in the picture.

You have to find the value of the function f(x) at x=-2.

From the graph, at x = -2, value of y = 2.

Thus, the value of function is:

$\boxed{\textbf{ \red {y = f(-2) = 2}}}$

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A theater group made appearances in two cities. The hotel charge before tax in the second city was $500 lower than in the first.

Mazyrski [523]

Answer:

First city: $5,500

Second city: $5,000

Step-by-step explanation:

Let's define x as the hotel price in the first city and y the hotel price in the second city. We can start with this equation:

y = x - 500 (The hotel before tax in the 2nd city was $500 lower than in the 1st.)

Then we can say

0.065x + 0.045y = 582.50 (the sum of the tax amounts were $582.50)

We place the value of y from the first equation in the second equation:

0.065x + 0.045 (x - 500) = 582.50

0.065x + 0.045x - 22.50 = 582.50 (simplifying and adding 22.5 on each side)...

0.11x = 605

x = 5,500

The cost of the first hotel was $5,500

Thus, the cost of the second hotel was $5,000 (x - 500)

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3 years ago

Solve the equation 3(x-3)=6x+3

AnnZ [28]

why is no one answering I have the same question

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3 years ago

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What is the expression using factorials. 45

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10! / (!2 * 8!) = '10 choose 10 choose 8

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4 years ago

Solve the triangle. Round side measure to the nearest tenth and angle measures to the nearest degree.

shutvik [7]

First calculate the missing angle $\alpha$ . By knowing all angles in triangle have a sum of 180°.

$\alpha=180-(\gamma+\beta)$
$\alpha=180-(90+49)=\boxed{41}$

Now we required to use angle functions in a right triangle. The cosine of $\beta$ is equal to the relation of side $a$ and hypotenuse $c$ .

Now we solve this for hypotenuse.

$\cos(\beta)=\frac{a}{c}$

$c=\frac{a}{\cos(\beta)}$

Now put in the numbers.

$c=\frac{9}{\cos(49)}\approx\boxed{13.7}$

So we know the length of hypotenuse and length of side $a$ therefore side $b$ can be calculated using Pythagorean theorem: $c^2=a^2+b^2$ .

Solve for side $b$ .

$c^2=a^2+b^2$

$b=\sqrt{c^2-a^2}$

$b=\sqrt{13.7^2-9^2}\approx\boxed{9.7}$

So there you go. If you have any questions feel free to ask.

r3t40

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4 years ago

I need some help with my lesson pleaseee

andrezito [222]

It is the second choice

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4 years ago

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