I suspect 4/2 should actually be 4/3, since 4/2 = 2, while 4/3 would make V the volume of a sphere with radius r. But I'll stick with what's given:





In Mathematica, you can check this result via
D[4/2*Pi*r^3, r]
Answer:
D 2+6x
Step-by-step explanation:
-2/3(-3-9x)
(-2/3×-3)+(-2/3×-9x)
6/3+18x/3 = 2 + 6x
The sum of 10 and a subtraction of 4 from 6.
The answer is W>33 this is as simplified at it can be