In parallelogram ABCD, m∠ABD = 83°, m∠BDA = 34°, and m∠BCD = °.
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Answer:
63°
Step-by-step explanation:
We are told in the above question that for parallelogram ABCD, ∠ABD=83° and ∠BDA=34°.
To get the above angles, parallelogram ABCD was split into two triangles by a diagonal given us ∆ABD and ∆BCD
Remember that angles in a triangle = 180°
∆ABD has ∠ABD=83°, ∠BDA=34° and ∠DAB
180° = ∠ABD + ∠BDA+ ∠DAB
180° = 83° + 34° + ∠DAB
∠DAB = 180°-117°
=63°
Since ∆ABD and ∆BCD are similar triangles because they are from one parallelogram,
∠DAB = ∠BCD
= 63°
Therefore, the measure of the angle BCD is 63°.
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n=14, m=3, p=2
Further explanation:
We have to solve the left hand side to check what will be the values of n,m and p
So,
Given
Taking LCM
We divide the LCM with denominator of first fraction and multiply the remainder with the numerator => 14
Then divide the LCM by denominator of second fraction and multiply the remainder with numerator => 3x
Comparing both terms we get
n=14
n=3
p=2
Keywords: Polynomial, Expressions
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