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Elden [556K]
3 years ago
14

Write in​ point-slope form an equation of the line through the pair of points. (3,12) and (5,9)

Mathematics
1 answer:
horrorfan [7]3 years ago
4 0

Answer:

\large\boxed{y=-\dfrac{3}{2}x+16\dfrac{1}{2}\to y=-1.5x+16.5}

Step-by-step explanation:

The slope-intercept form of an equation of a line:

y=mx+b

<em>m</em><em> - slope</em>

<em>b</em><em> - y-intercept</em>

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (3, 12) and (5, 9).

Substitute:

m=\dfrac{9-12}{5-3}=\dfrac{-3}{2}=-\dfrac{3}{2}

Put the value of a slope and coordinates of the point (3, 12) to the equation of a line:

12=-\dfrac{3}{2}(3)+b

12=-\dfrac{9}{2}+b

12=-4\dfrac{1}{2}+b          <em>add 4\dfrac{1}{2} to both sides</em>

16\dfrac{1}{2}=b\to b=16\dfrac{1}{2}

Finally:

y=-\dfrac{3}{2}x+16\dfrac{1}{2}

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Find Slope:
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\text {Slope = }  \dfrac{2 - 0}{0-(-2)}

\text {Slope = }  1

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Substitute Slope = 1 into y = mx + b:
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Answer: The value of m+b is 3.
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