Answer:
Mesopotamia
Step-by-step explanation:
The oldest clay tablets with mathematics date back over 4,000 years ago in Mesopotamia. The oldest written texts on mathematics are Egyptian papyruses.
Answer:
(x+2) (5x)
Step-by-step explanation:
the way I factor is the products of a*c added together equals b. so the products if (5*2) 10 equals 11. so 10 and 1 are the 2 products that add into 11. Now we put that into the equation. 5x^2+10x+1x+2 now take the two haves until you can't factor them any more 5x(x+2) (x+2). now take the repeated factor and outside factors to get (5x) and (x+2)
Answer:
multiply s by t
Step-by-step explanation:
you just multiply s times t and get your answer
34/3 = 11 1/3 = 11.3333....
Answer:
Recall that a relation is an <em>equivalence relation</em> if and only if is symmetric, reflexive and transitive. In order to simplify the notation we will use A↔B when A is in relation with B.
<em>Reflexive: </em>We need to prove that A↔A. Let us write J for the identity matrix and recall that J is invertible. Notice that 
. Thus, A↔A.
<em>Symmetric</em>: We need to prove that A↔B implies B↔A. As A↔B there exists an invertible matrix P such that 
. In this equality we can perform a right multiplication by 
and obtain 
. Then, in the obtained equality we perform a left multiplication by P and get 
. If we write 
and 
we have 
. Thus, B↔A.
<em>Transitive</em>: We need to prove that A↔B and B↔C implies A↔C. From the fact A↔B we have and from B↔C we have 
. Now, if we substitute the last equality into the first one we get
.
Recall that if P and Q are invertible, then QP is invertible and 
. So, if we denote R=QP we obtained that
. Hence, A↔C.
Therefore, the relation is an <em>equivalence relation</em>.
