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3 years ago

6

At 6:00 a.m., the outside temperature was –14.5⁰. By noon, the outside temperature had dropped 8.6⁰. What was the outside temper

ature at noon? 6.9⁰ –5.9⁰ –23.1⁰ 23.1

1 answer:

Lerok [7]3 years ago

3 0

The answer is -23.1°

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$Solution,solve\:for\:d,\:d-10-2d+7=8+d-10-3d\quad :\quad d=1$

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$d-10-2d+7=8+d-10-3d$

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