C hope that helps have a good one and stay 28 - 6973
Answer below (B) Hope it’s helpful
Answer:
25
Step-by-step explanation:
So first we'll input the numbers then since we have them.
5(1) + 3(7) - 1^3
So we're going to use the order of operations here first (PEMDAS) and start with the exponent because the parenthesis I used just represent multiplication. And 1 to the power of anything is still 1. Even 1^1000000000000000000000000000.....
It's still 1.
So now we have this:
5(1) + 3(7) - 1
Now we can multiply:
5 + 21 - 1
Then, add and subtract:
26 - 1
To get:
25
Given:
Origin of the clock face (0,0)
label 12 point (0,5)
I am assuming that the radius of the clock is 5 units.
Label 6 should be placed on the point (0,-5). The point of label 12 should be reflected across the x-axis and labeled as 6 of the clock face.
Answer:
$43,625
Step-by-step explanation:
Hello,
The question is a direct application of compound interest and we'll approach this question using the formula of compound interest.
A = P(1 + r/n)^nt
A = compound interest
P = principal
r = rate of the interest
n = number of times compounded
t = time interval for the money to be compounded.
Data;
A = ?
P = $2,500
r = 10% = 0.1
n = 1 (since it's compounded annually)
T = 30 years
A = 2,500 [1 + (0.1 / 1)]^(1 × 30)
A = 2,500 × [1 + 0.1]³⁰
A = 2,500 × 1.1³⁰
A = 2,500 × 17.45
A = $43,625
In 30 years, Jenna would've saved $43,625