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Alchen [17]
3 years ago
7

Solve x/2 + y/3 = 1 for x

Mathematics
2 answers:
Inessa05 [86]3 years ago
7 0

Answer:

First, you have to make both fractions the same denorminators :

\frac{x}{2}  +  \frac{y}{3}  = 1

\frac{x  \times 3}{2 \times 3}  +  \frac{y \times 2}{3 \times 2}  = 1

\frac{3x}{6}  +  \frac{2y}{6}  = 1

Next, you have make them into 1 fraction :

\frac{3x + 2y}{6}  = 1

Then, you have to multiply both sides by 6, in order to get rid fraction :

\frac{3x + 2y}{6}  \times 6 = 1 \times 6

3x + 2y = 6

Lastly, you have to move all the unrelated terms to the other side :

3x + 2y = 6

3x = 6 - 2y

x =  \frac{6}{3}  -  \frac{2}{3} y

x = 2 -  \frac{2}{3} y

Therefore, the value of x is :

x = 2 -  \frac{2}{3} y

Ivenika [448]3 years ago
5 0

Answer:

Step-by-step explanation:

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Read 2 more answers
Evaluate the following expression:<br><br> 5z + 3n - z^3<br><br> n = 7<br><br> z = 1
frutty [35]

Answer:

25

Step-by-step explanation:

So first we'll input the numbers then since we have them.

5(1) + 3(7) - 1^3

So we're going to use the order of operations here first (PEMDAS) and start with the exponent because the parenthesis I used just represent multiplication. And 1 to the power of anything is still 1. Even 1^1000000000000000000000000000.....

It's still 1.

So now we have this:

5(1) + 3(7) - 1

Now we can multiply:

5 + 21 - 1

Then, add and subtract:

26 - 1

To get:

25

8 0
3 years ago
Greg is designing the clock face for a homemade clock. Using the center of the clock face as the origin, he places the label 12
Viktor [21]
Given:
Origin of the clock face (0,0)
label 12 point (0,5)

I am assuming that the radius of the clock is 5 units. 

Label 6 should be placed on the point (0,-5). The point of label 12 should be reflected across the x-axis and labeled as 6 of the clock face.
5 0
3 years ago
Jenna saves $2,500 per year in an account that earns 10% interest per year, compounded annually. Jenna will have saved in 30 yea
CaHeK987 [17]

Answer:

$43,625

Step-by-step explanation:

Hello,

The question is a direct application of compound interest and we'll approach this question using the formula of compound interest.

A = P(1 + r/n)^nt

A = compound interest

P = principal

r = rate of the interest

n = number of times compounded

t = time interval for the money to be compounded.

Data;

A = ?

P = $2,500

r = 10% = 0.1

n = 1 (since it's compounded annually)

T = 30 years

A = 2,500 [1 + (0.1 / 1)]^(1 × 30)

A = 2,500 × [1 + 0.1]³⁰

A = 2,500 × 1.1³⁰

A = 2,500 × 17.45

A = $43,625

In 30 years, Jenna would've saved $43,625

6 0
4 years ago
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