Answer:
(0, -10)
Step-by-step explanation:
If you add both together from x - y, each add up to their own value. For example, -5, and -9 would be -14. It's quite simple. I hope this helps. I'm sorry if this is not what you are looking for.
Answer:

Step-by-step explanation:
<u>The full question:</u>
<em>"A committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer. each member is equally likely to serve in any of the positions. Three members are randomly selected and assigned to be the new chairman, ranking member, and treasurer. What is the probability of randomly selecting the three members who currently hold the positions of chairman, ranking member, and treasurer and reassigning them to their current positions?"</em>
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The permutation of choosing 3 members from a group of 11 would be:
P(n,r) = 
Where n would be the total [in this case n is 11] & r would be 3
Which is:
P(11,3) = 
So there are total of 990 possible way and there is ONLY ONE WAY for them to be reassigned. Hence the probability would be:
1/990
If you would like to know how many people attended the reunion last year, you can calculate this using the following steps:
125% of last year's attendance is 160 people
125% of x is 160
125% * x = 160
125/100 * x = 160 /*100/125
x = 160 * 100 / 125
x = 128 people (last year)
Result: 128 people attended the reunion last year.
Answer:
The first one.
Step-by-step explanation:
Answer:
BC = 8 and EF = 8.
Step-by-step explanation:
Since triangle ABC and DEF are congruent to each other, BC corresponds with EF (as determined by the triangle names).
Set BC and EF equal to each other.
x + 6 = 3x + 2
Subtract x from both sides.
6 = 2x + 2
Subtract 2 from both sides.
4 = 2x.
Divide 2 on both sides.
x = 2.
Substitute 2 for x.
BC = 2 + 6
BC = 8
Since we already know that EF is congruent to BC, EF is also 8.
EC = 3(2) + 2
EC = 6 + 2
EC = 8