Answer:
I believe the answer is b
Step-by-step explanation: I think the answer is b because he gets $5 every week and he already has $25 the only thing we dont know is the weeks and you multiply 5 by the weeks so, 5(how much he gets each week) times x (The amount of weeks) plus 25(the amount he already has) equals y(the amount of everything put together)
Answer:
c
Step-by-step explanation:
I hope this helpssssssss
Answer:
6 inches
Step-by-step explanation:
The volume of a triangular pyramid can be found using
v=1/3bh
where b is the area of the base, and h is the height
We know the volume is 12, so let's find the area of the base
The area of a triangle can be found using:
a=bh/2
We know the base is 4, and the the height is 3, so we can substitute them in
a=4*3/2
a=12/2
a=6
Now, we can solve for the height
v=1/3bh
Substitute 12 in for v, and 6 in for b
12=1/3(6h)
Multiply both sides by 3
3*12=1/3(6h)*3
36=6h
Divide both sides by 6
h=6
The height is 6 inches
Answer:
Please check the explanation
Step-by-step explanation:
Given the function
Given that the output = -3
i.e. y = -3
now substituting the value y=-3 and solve for x to determine the input 'x'
switch sides
Add 1 to both sides
![\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}](https://tex.z-dn.net/?f=%5Cmathrm%7BFor%5C%3A%7Dg%5E3%5Cleft%28x%5Cright%29%3Df%5Cleft%28a%5Cright%29%5Cmathrm%7B%5C%3Athe%5C%3Asolutions%5C%3Aare%5C%3A%7Dg%5Cleft%28x%5Cright%29%3D%5Csqrt%5B3%5D%7Bf%5Cleft%28a%5Cright%29%7D%2C%5C%3A%5Csqrt%5B3%5D%7Bf%5Cleft%28a%5Cright%29%7D%5Cfrac%7B-1-%5Csqrt%7B3%7Di%7D%7B2%7D%2C%5C%3A%5Csqrt%5B3%5D%7Bf%5Cleft%28a%5Cright%29%7D%5Cfrac%7B-1%2B%5Csqrt%7B3%7Di%7D%7B2%7D)
Thus, the input values are:
![x=-\sqrt[3]{2}+5,\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}-i\frac{\sqrt[3]{2}\sqrt{3}}{2},\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}+i\frac{\sqrt[3]{2}\sqrt{3}}{2}](https://tex.z-dn.net/?f=x%3D-%5Csqrt%5B3%5D%7B2%7D%2B5%2C%5C%3Ax%3D%5Cfrac%7B%5Csqrt%5B3%5D%7B2%7D%5Cleft%281%2B5%5Ccdot%20%5C%3A2%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%5Cright%29%7D%7B2%7D-i%5Cfrac%7B%5Csqrt%5B3%5D%7B2%7D%5Csqrt%7B3%7D%7D%7B2%7D%2C%5C%3Ax%3D%5Cfrac%7B%5Csqrt%5B3%5D%7B2%7D%5Cleft%281%2B5%5Ccdot%20%5C%3A2%5E%7B%5Cfrac%7B2%7D%7B3%7D%7D%5Cright%29%7D%7B2%7D%2Bi%5Cfrac%7B%5Csqrt%5B3%5D%7B2%7D%5Csqrt%7B3%7D%7D%7B2%7D)
And the real input is:
![x=-\sqrt[3]{2}+5](https://tex.z-dn.net/?f=x%3D-%5Csqrt%5B3%5D%7B2%7D%2B5)
