What resources can be shared over a computer network?

Programming challenge description: Write a program that, given two binary numbers represented as strings, prints their sum in bi

Lubov Fominskaja [6]

Answer:

The program to this question can be given as:

Program:

#include<iostream> //include header file

using namespace std;

string add(string a, string b) //define add function

{ //declare variable

string result = "";

int sum = 0,k,l;

cahr x;

k= a.size() - 1;

l = b.size() - 1;

while (k>= 0 || l>= 0 || sum == 1) //loop

{

//addition

sum= sum+ ((k >= 0)? a[k] - '0': 0);

sum= sum+ ((l >= 0)? b[l] - '0': 0);

x=sum%2;

result=(x+'0') +result;

// Compute carry

sum =sum/ 2;

// Move to next digits

k--;

l--;

}

return result; //return value

}

int main() //main method

{

string a,b; //string variable

cout<<"Enter first binary digit: "; //message.

cin>>a; //input from user

cout<<"Enter Second binary digit: "; //message.

cin>>b; //input from user

cout <<"Addition :"<<add(a, b)<<endl; //print addition

return 0;

}

Output:

Enter first binary digit: 1101

Enter Second binary digit: 100

Addition :10001

Explanation:

In the above c++ program first, we include the header file. Then we define the add function in the add function we add two binary digits by passing value as arguments. In this function, we define a variable that is used on the addition of binary numbers. In this function we define the loop in the loop we check if two binary number is 1 then it will print 0 and pass 1 as the carry. after performing addition it will return value. In the main function, we take two binary numbers from the user and pass the value to the function and print function return value.

8 0

4 years ago

Write an efficient C++ function that takes any integer value i and returns 2^i ,as a long value. Your function should not multip

Ilya [14]

Answer:

long power(int i)

{

return pow(2,i);

}

Explanation:

The above written function is in C++.It does not uses loop.It's return type is long.It uses the function pow that is present in the math library of the c++.It takes two arguments return the result as first argument raised to the power of second.

for ex:-

pow(3,2);

It means 3^2 and it will return 9.

4 0

3 years ago

A diagnostic program built into a computer to test the hardware components before the computer boots up

Allushta [10]

BIOS thank me later

8 0

3 years ago

In unreal engines which class should be used to define the rules of the game

mel-nik [20]

Answer: The number of players and spectators present, as well as the maximum number of players and spectators allowed.

Explanation: players

8 0

3 years ago

Pick the 3 correct Python functions that parse and output only the date and time part of each log in log.txt as follows.

Mila [183]

Answer:

1, 4, 5

Explanation:

parse2:

. In this case it's passing "r" as an argument, which really does absolutely nothing, because whenever you call open("file.txt") it defaults to reading mode, so all you're doing is explicitly passing the "r". So let's look at the first line. Whenever you call str.split() without any arguments, by default it splits it by empty text, and filters any empty text. So str.split() is not the same as str.split(" ") although it has similar behavior. " ".split(" ") will output ['', '', '', '', '', ''], while " ".split() will output []. So in this case the line.split() will split the string '10.1.2.1 - car [01/Mar/2022:13:05:05 +0900] "GET /python HTTP/1.0" 200 2222' into the list ['10.1.2.1', '-', 'car', '[01/Mar/2022:13:05:05', '+0900]', '"GET', '/python', 'HTTP/1.0"', '200', '2222']. As you can see the the data is split into two pieces of text, AND they include the brackets in both strings. So when it gets the 3 index and strips it of the "[]" it will have the incomplete date

parse3:

In this instance the "r" does nothing as mentioned before the "r" is already defaulted whenever you call open("file.txt") so open("file.txt") is the same as open("file.txt", "r"). So in this case we won't be working left to right, we're going inside the brackets first, kind of like in math you don't don't work left to right in equation 3 + 3(2+3). You work in the brackets first (inside brackets you do left to right). So the first piece of code to run is the line.split("[" or "]"). I actually kind of misspoke here. Technically the "[" or "]" runs first because this doesn't do what you may think it does. The or will only return one value. this is not splitting the line by both "[" and "]". The, or will evaluate which is true from left to right, and if it is true, it returns that. Since strings are evaluated on their length to determine if they're true. the "[" will evaluate to true, because any string that is not empty is true, if a string is empty it's false. So the "[" will evaluate to true this the "[" or "]" will evaluate to "[". So after that the code will run line.split("[") which makes the list: ['10.1.2.1 - car ', '01/Mar/2022:13:05:05 +0900] "GET /python HTTP/1.0" 200 2222']. Now the [3:5] will splice the list so that it returns a list with the elements at index 3 (including 3) to 5 (excluding 5). This returns the list: [], because the previous list only has 2 elements. There are no elements at index 3 to 5 (excluding 5). So when you join the list by " ", you'll get an empty string

parse4:

So I'm actually a bit confused here, I thought the "r+" would open the file in read-writing mode, but maybe this is a different version of python I have no idea, so I'm going to assume it is reading/writing mode, which just means you can read and write to the file. Anyways when you split the line by doing line.split(), as mentioned before it will split by empty spaces and filter any empty spaces. This line will return: ['10.1.2.1', '-', 'car', '[01/Mar/2022:13:05:05', '+0900]', '"GET', '/python', 'HTTP/1.0"', '200', '2222']. and then you splice the list from indexes 3 to 5 (excluding 5). This will return the list: ['[01/Mar/2022:13:05:05', '+0900]'] which has the two pieces of information you need for the date. Now it joins them by a space which will output: '[01/Mar/2022:13:05:05 +0900]'. Now when you strip the "[]" you get the string: '01/Mar/2022:13:05:05 +0900' which is the correct output!

parse 5:

So in this example it's using re.split. And the re.split is splitting by "[" or "]" which is what re.split can be used for, to split by multiple strings, which may be confused by string.split("[" or "]") which is not the same thing as explained above what the latter does. Also the reason there is a backslash in front of the [ and ] is to escape it, because normally those two characters would be used to define a set, but by using a \ in front of it, you're essentially telling regex to interpret it literally. So in splitting the string by "[" and "]" you'll get the list: ['10.1.2.1 - car ', '01/Mar/2022:13:05:05 +0900', ' "GET /python HTTP/1.0" 200 2222'] which has 3 elements, since it was split by the [ and the ]. The second element has the date, so all you need to do is index the list using the index 1, which is exactly what the code does

8 0

2 years ago