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Law Incorporation [45]
2 years ago
6

A voice engineer is setting up a Cisco 2951 Integrated Services Router with Cisco Unified Communications Manager Express. To ena

ble voice features for SIP endpoints, which command the engineer enter
Computers and Technology
1 answer:
o-na [289]2 years ago
8 0

Answer:

voice service voip

Explanation:

Voice over Internet Protocol feature allows users to make voice calls by making use of a broadband internet connection. The Voice engineer is setting up a Cisco 2951 Integrated Services Router with Cisco Unified Communications Manager Express, which happens to fall under broadband internet connection and hence the command the engineer will enter must be a voice service voip.

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Write a Java program to create a class called Cars. The class should include three instance variables: makes (type: String), mod
Fiesta28 [93]

Answer:

Explanation:

This code was written in Java. It creates the Cars class with the requested variables and methods. It also creates the TestCars class which asks the user for the necessary inputs and then creates three Cars objects and passes the input values to the constructors. Finally, it uses the show() method on each object to call the information. A test has been created and the output can be seen in the attached image below.

import java.util.Scanner;

class TestCars{

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.print("Enter Car Make: ");

       String make1 = in.next();

       System.out.print("Enter Car Model: ");

       String model1 = in.next();

       System.out.print("Enter Car Year: ");

       int year1 = in.nextInt();

       System.out.print("Enter Car Make: ");

       String make2 = in.next();

       System.out.print("Enter Car Model: ");

       String model2 = in.next();

       System.out.print("Enter Car Year: ");

       int year2 = in.nextInt();

       System.out.print("Enter Car Make: ");

       String make3 = in.next();

       System.out.print("Enter Car Model: ");

       String model3 = in.next();

       System.out.print("Enter Car Year: ");

       int year3 = in.nextInt();

       Cars car1 = new Cars(make1, model1, year1);

       Cars car2 = new Cars(make2, model2, year2);

       Cars car3 = new Cars(make3, model3, year3);

       car1.show();

       car2.show();

       car3.show();

   }

}

class Cars {

   String makes, models;

   int years;

   public Cars(String makes, String models, int years) {

       this.makes = makes;

       this.models = models;

       this.years = years;

   }

   public void show() {

       System.out.println("Car's make: " + this.makes);

       System.out.println("Car's model: " + this.models);

       System.out.println("Car's year: " + this.years);

   }

}

5 0
3 years ago
What is the best free game designing program for windows
Nadusha1986 [10]
Python, Unity 3D, C++Notepad
8 0
3 years ago
Courts are struggling with the privacy implications of GPStracking. In 2009, New York’s highest court held that policeofficers m
aniked [119]

Answer:

warrant

Explanation:

New York State's highest court ruled in 2009 that tracking a person via the global positioning system (GPS) without a warrant violated his right to privacy.

6 0
3 years ago
Write a loop that reads c-strings from standard input where the c-string is either "land", "air", or "water". The loop terminate
Anvisha [2.4K]

Answer:

I am writing a C++ code.        

#include <iostream> // for input output functions

using namespace std; // identifies objects like cin cout

int main() { //start of main() function body

string c_string; // stores the string entered by user from land water or air

int land=0; // contains the number of times land string is read in

int air=0; //contains the number of times air string is read in

int water = 0; //contains the number of times water string is read in

cin>>c_string; //reads the string entered by user from air water or land

/*while loop continues to execute until user enters xxxxx or maximum length of a string exceeds 8 */

while(c_string!= "xxxxx" && c_string.length()<=8) {

if(c_string=="land"){ // if string entered by user is land

land = land + 1;} //counts and increments each occurrence of land string by 1

else if(c_string=="air"){// if string entered by user is air

air = air + 1;}// counts and increments each occurrence of string air by 1

else if(c_string=="water"){// if string entered by user is water

water = water + 1;}//counts and increments each occurrence of air by 1

cin>>c_string;}

/* keeps reading the string entered by user from land air or water, until the loop breaks after the user enters xxxxx or user enters a string whose length is greater than 8 */

//prints the number of times land, air and water are read in

cout << "land:"<<land;

cout << endl<<"air:"<<air;

cout << endl<< "water:"<<water; }                      

                                                                                     

Explanation:

Everything is well explained in the comments above.

The program prompts the user to input strings. These strings are either land air or water. The while loop continues to read the input strings until user enters xxxxx or the string entered by user exceeds the length 8. Both these terminating conditions are added in the while loop. After the loop terminates, the number of times land, air and water strings are read is displayed on the output screen. Any other string entered by user other than these 3 is ignored. The program along with the output is attached.

3 0
3 years ago
Q10: You cannot rename a compressed folder.
user100 [1]
<h2>Answer:</h2><h2>Oh yes you can. </h2>

Click slowly twice the folder.

Right click and choose rename.

4 0
3 years ago
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