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Vera_Pavlovna [14]

2 years ago

6

The sixth-graders at Ruben's school got to choose between a field trip to a museum and a field trip to a factory. 30 sixth-grade

rs picked the museum. If there are 50 sixth-graders in all at Ruben's school, what percentage of the sixth-graders picked the museum?

1 answer:

earnstyle [38]2 years ago

3 0

60 percent!

I hope this helped!

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Can someone correct me I don't know if I got it right

Angelina_Jolie [31]

Answer:

yup

Step-by-step explanation:

8 0

2 years ago

16x+4(x-5) how do I solve this.?

Nadusha1986 [10]

Answer:20x-20

16x+4(x-5)

4(x-5)=4x-20

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20x-20

8 0

3 years ago

Read 2 more answers

This extreme value problem has a solution with both a maximum value and a minimum value. use lagrange multipliers to find the ex

noname [10]

$L(x,y,z,\lambda)=10x+10y+2z+\lambda(5x^2+5y^2+2z^2-42)$

$L_x=10+10\lambda x=0\implies1+\lambda x=0$

$L_y=10+10\lambda y=0\implies1+\lambda y=0$

$L_z=2+4\lambda z=0\implies1+2\lambda z=0$

$L_\lambda=5x^2+5y^2+2z^2-42=0$

$\begin{cases}L_x=0\\L_y=0\\L_z=0\end{cases}\implies1+\lambda x=1+\lambda y=1+2\lambda z=0\implies x=y=2z$

$5x^2+5y^2+2z^2=5(2z)^2+5(2z)^2+2z^2=42z^2=42\implies z^2=1$

$z^2=1\implies z=\pm1\implies x=y=\pm2$

There are two critical points, at which we have

$f\left(2,2,1\right)=42\text{ (a maximum value)}$

$f\left(-2,-2,-1\right)=-42\text{ (a minimum value)}$

3 0

3 years ago

Find the measure of the marked acute angle to the nearest degree

Setler79 [48]

Answer: 62°
Solution:
tan x =34/18
x=tan^-1 (34/18)
x=62°

5 0

3 years ago

How would solve 2s + s = 36

Lesechka [4]

2s + s = 36
3s = 36
s = 36/3
s = 12

7 0

2 years ago