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Vera_Pavlovna [14]

3 years ago

6

The sixth-graders at Ruben's school got to choose between a field trip to a museum and a field trip to a factory. 30 sixth-grade

rs picked the museum. If there are 50 sixth-graders in all at Ruben's school, what percentage of the sixth-graders picked the museum?

1 answer:

earnstyle [38]3 years ago

3 0

60 percent!

I hope this helped!

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0.000006 write each number in scientific notation

aalyn [17]

$6\times 10^-^6$

5 0

3 years ago

A television network is deciding whether or not to give its newest television show a spot during prime viewing time at night. If

Alinara [238K]

Answer:

Test statistic z= 1.708

Step-by-step explanation:

given that a television network is deciding whether or not to give its newest television show a spot during prime viewing time at night. If this is to happen, it will have to move one of its most viewed shows to another slot.

Sample size n = 827

Sample proportion p = $\frac{438}{827} \\=0.5297$

$H_0: p =0.5\\H_a: p >0.5$

(right tailed test)

This is because they would be interested if more than half viewers are ready for the change

Test statistic = Z = p difference/std error

p difference = 0.0297

Std error = $\sqrt{\frac{pq}{n} } \\=\sqrt{\frac{0.5*0.5}{827} } \\=0.0174$

Z =1.708

p valu e= 0.9562

Since p >0.05 we fail to reject H0

Test statistic z= 1.708

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=538%20%5Ctimes%204%20%5C%5C%20%20%5C%5C%20214%20%5Ctimes%208%20%5C%5C%20%20%5C%5C%203721%20%5C

Shalnov [3]

Answer:

Step-by-step explanation:

multiply $(538)(4)=2152\\(214)(8)=1712\\(3721)(7)=26047\\(7956)(8)=63648$

7 0

3 years ago

The distribution of the amount of a certain brand of soda in 16 OZ bottles is approximately normal with a mean of 16.12 OZ and a

elena-14-01-66 [18.8K]

Answer: 90.82%

Step-by-step explanation:

Given : The distribution of the amount of a certain brand of soda in 16 OZ bottles is approximately normal .

Mean : $\mu=16.12\text{ OZ}$

Standard deviation: $\sigma=0.09\text{ OZ}$

Let X be the random variable that represents the amount of soda in bottles.

Formula for z-score : $z=\dfrac{x-\mu}{\sigma}$

Z-score for 16 oz: $z=\dfrac{16-16.12}{0.09}=-1.33$

Using the standard normal z-distribution table , the probability that the soda bottles that contain more than the 16 OZ is given by :_

$P(x>60)=P(z>-1.33)=1-P(x\leq-1.33)=1-0.0917591=0.9082409\approx0.9082\approx90.82\%$

Hence, the percentage of the soda bottles that contain more than the 16 OZ advertised is 90.82% .

8 0

3 years ago

Consider a collection of envelopes consisting of 2 red envelopes, 2 blue envelopes, 2 green envelopes, and 3 yellow envelopes

77julia77 [94]

The probability that all three randomly selected envelopes are yellow without replacement is 1/84.

<h3>What is a combination?</h3>

It is an arrangement of a set of numbers from a total set where the order of the set is not relevant.

We have,

2 red envelopes

2 blue envelopes

2 green envelopes

3 yellow envelopes.

Total number of envelopes = 9

The probability that all three randomly selected envelopes are yellow without replacement.

= $\frac{^3C_1}{^9C_1} \frac{^2C_1}{^8C_1} \frac{^1C_1}{^7C_1}$

= (3/9) x (2/8) x (1/7)

= (3x2x1)/(9x8x7)

= 1/84

Thus,

The probability that all three randomly selected envelopes are yellow without replacement is 1/84.

Learn more about combination here:

brainly.com/question/14355408

#SPJ1

4 0

1 year ago