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Elena-2011 [213]
3 years ago
13

two squares of the side 10 cm were joined together to form a rectangle. Calculate the perimeter of the rectangle.​

Mathematics
1 answer:
VLD [36.1K]3 years ago
7 0

Answer:

Step-by-step explanation:

If they were joined together, wouldn't the length of both squares combined be 20cm?

Therefore, it'd be (10+20+10+20) for the perimeter.

60cm.

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Karen gave an equal amount of m and m's to herself and four friends. Each person receives m and m's equivalent to the largest on
Mariana [72]

Answer:

Karen had 45 m and m's candy.

Step-by-step explanation:

Let the number of m and m's candy be 'x'.

Now given:

Karen gave an equal amount of m and m's to herself and four friends.

So we can say that;

Number of people m and m's candy distributed equally = 5

Also Given:

Each person receives m and m's equivalent to the largest one digit number.

Now we know that;

Largest one digit number is 9.

So we can say that;

Each person receives m and m's = 9

We need to find number of m and m's Karen have.

Solution:

So we can say that;

Total number of m and m's Karen have is equal to Number of people m and m's candy distributed equally multiplied by number of m and m's can each person receives.

framing in equation form we get;

Total number of m and m's Karen had = 9\times5 = 45

Hence Karen had 45 m and m's candy.

8 0
3 years ago
In ^ABC, AB = 5 and AC = 14. Find m
VikaD [51]

Answer:

im not sure i understand the question, could you be more specific?

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
What are the approximate values of the minimum and maximum points of f(x) = x5 − 10x3 + 9x on [-3,3]?
nika2105 [10]

Answer:

Minimum : -37 at x=2.4 and

Maximum = 37 at x=-2.4.

Step-by-step explanation:

Given:

f(x)=x^5-10x^3+9x; [-3,3]

Explanation:

In order to find minimum/maximum of a function, we need to find the first derivative of the function and then set it equal to 0 to get critical points.

Therefore,

f'(x)=5x^4-30x^2+9

Setting derivative equal to 0, we get

5x^4-30x^2+9=0

On applying quadratic formula, we get

x=2.4, -2.4, -0.7, 0.7.

So, those are critical points of the given function.

Plugging the values x=2.4, -2.4, -0.7, 0.7, -3 and 3 in above function, we get

f(2.4)=(2.4)^5-10(2.4)^3+9(2.4)= -37.01376   : Minimum.

f(-2.4)=(-2.4)^5-10(-2.4)^3+9(-2.4)= 37.01376 : Maximum.

f(0.7)=(0.7)^5-10(0.7)^3+9(0.7) = 3.03807

f(-0.7)=(-0.7)^5-10(-0.7)^3+9(-0.7) = -3.03807

f(-3)=(-3)^5-10(-3)^3+9(-3) =0

f(3)=(3)^5-10(3)^3+9(3) =0

Therefore the approximate values of the minimum and maximum points of f(x) = x^5- 10x^3+ 9x on [-3,3] are:

Minimum : -37 at x=2.4 and

Maximum = 37 at x=-2.4.


7 0
4 years ago
PLEASE HELP ITS DUE IN 2 HOURS, I NEED THIS, WILL GIVE BRAINLIEST.
Evgesh-ka [11]

I'm sorry I only know one of them

4 0
3 years ago
A relay race covers 1 1/2 miles, and each runner on a team will run 1/4 of a mile. How many runners are needed for a team?
Semenov [28]
6 runners are needed for the team 
8 0
3 years ago
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