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Pavel [41]
3 years ago
8

Need help I don’t know how to do it

Mathematics
1 answer:
neonofarm [45]3 years ago
5 0

Step-by-step explanation:

the easiest way (at least for me) is to stay with the point-slope form and then transform it to get the slope-intercept form.

the general slope-intercept form is

y = ax + b

a being the slope, and b the y-intercept (the y-value when x = 0).

the general point-slope form is

y - y1 = a(x - x1)

a is again the slope, and (x1, y1) is a point on the line.

so,

1.

y - 1 = 2(x - 4)

y = 2(x - 4) + 1 = 2x - 8 + 1 = 2x - 7

y = 2x - 7

2.

y - 4 = 1/2 × (x - 2)

y = 1/2 × (x - 2) + 4 = x/2 - 1 + 4 = x/2 + 3

y = 1/2 × x + 3 or x/2 + 3

3.

y - 0 = 2/3 × (x - -6)

y = 2/3 × x + 4 or 2x/3 + 4

4.

y - -1 = -3/4 × (x - -8)

y + 1 = -3/4 × x - 6

y = -3/4 × x - 7 or -3x/4 - 7

5.

y - -3 = -1×(x - 4)

y + 3 = -x + 4

y = -x + 1

6.

y - -9 = 4(x - 0)

y + 9 = 4x

y = 4x - 9

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vlada-n [284]

Answer:

<u>y = -x² + 4</u>

Step-by-step explanation:

The equation of the parabola in the vertex form is:

y = a (x-h)² + k

Where: (h,k) the coordinates of the vertex & a is a multiplier

The parabola has a vertex at ( 0,4 )

So, h = 0 , k = 4

∴ y = a (x-0)² + 4

∴ y = a x² + 4

The parabola passes through points ( 2,0 )

∴ 0 = a 2² + 4

∴ 4 a = -4  ⇒ a = -4/4 = -1

∴ y = -x² + 4

So, the equation of a parabola that has a vertex at ( 0,4 ) and passes through points ( 2,0 ) is <u>y = -x² + 4</u>

See the attached figure.

4 0
3 years ago
The solution set of 4x-(x+7)=2(x+3)​
maria [59]

Step-by-step explanation:

<h3><u>To</u><u> </u><u>Solve</u><u>:</u><u>-</u></h3>

\\ \tt{:}\leadsto 4x-(x+7)=2(x+3)

<h3><u>SOL</u><u>UTION</u><u>:</u><u>-</u></h3>

\\ \tt{:}\leadsto 4x-(x+7)=2(x+3)

\\ \tt{:}\leadsto 4x-x-7=2x+6

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7 0
3 years ago
Solve for x. |4x - 5| &gt; 7
trasher [3.6K]

Answer:

x>3

Step-by-step explanation:

|4x-5|>7

4x -5>7

4x >7+5

4x /4>12/4

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solution set={4,5,6,---}

8 0
3 years ago
Read 2 more answers
What is the answer to (14x-35)/7=7
IceJOKER [234]
Your not being very discriptive... BUT if you are finding 'x'...
(14x-35)/17=7
*17 *17
14x-35=119
+35 +35
14x=154
/14 /14
x=11
6 0
3 years ago
A stadium has 55,000 seats. Seats sell for ​$28 in Section​ A, ​$16 in Section​ B, and ​$12 in Section C. The number of seats in
salantis [7]
A=number of seats in section A
B=number of seats in section B
C=number of seats in section C

We can suggest this system of equations:

A+B+C=55,000
A=B+C                                      ⇒A-B-C=0
28A+16B+12C=1,158,000

We solve this system of equations by Gauss Method.

1             1              1               55,000
1            -1            -1                         0
28         16           12          1,158,000 


1             1              1               55,000
0            -2             -2             -55,000                                    (R₂-R₁)
0           12             16           382,000                                    (28R₁-R₂) 


1            1                1              55,000
0           -2              -2             -55,000
0            0                4               52,000                                     (6R₂+R₃)

Therefore:

4C=52,000
C=52,000/4
C=13,000


-2B-2(13,000)=-55,000
-2B-26,000=-55,000
-2B=-55,000+26,000
-2B=-29,000
B=-29,000 / -2
B=14,500.

A + 14,500+13,000=55,000
A+27,500=55,000
A=55,000-27,500
A=27,500.

Answer: there are 27,500 seats in section A, 14,500 seats in section B and 13,000 seats in section C.
3 0
3 years ago
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