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2 years ago

14

If the radius of a circle is increased by 100%, then the area is increased by:

1 answer:

shtirl [24]2 years ago

5 0

$A_1=\pi r^2\\\\R=2r\ then\ A_2=\pi R^2\to A_2=\pi(2r)^2=4\pi r^2\\\\A_2-A_1=4\pi r^2-\pi r^2=3\pi r^2=3A_1\\\\3=300\%\\\\Answer:(C).$

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What is the answer to this

LekaFEV [45]

$4 \dfrac{3}{5} \times \dfrac{5}{12} =$

$= \dfrac{23}{5} \times \dfrac{5}{12}$

You changed the mixed numeral into a fraction correctly.
Now you need to multiply the fractions.
Multiply the numerators together, and multiply the denominators together.

$= \dfrac{23 \times 5}{5 \times 12}$

Now we could multiply out the numerator and denominator, and then we'd need to reduce the fraction, but before we multiply, we see there is a factor of 5 both in the numerator and in the denominator, so we can reduce before we multiply.

$= \dfrac{23 \times 5}{12 \times 5}$

$= \dfrac{23}{12}$

$= 1 \dfrac{11}{12}$

6 0

2 years ago

Complete the table of inputs for the given function.

Alecsey [184]

Answer:

a. $x = \frac{3}{8}$

b. $g(0) = 3$

c. $x = 1$

d. $g(3) = -21$

Step-by-step explanation:

Given

$g(x) = 3 - 8x$

Solving (a): When g(x) = 0

Substitute 0 for g(x)

$g(x) = 3 - 8x$

$0 = 3 - 8x$

Solve for 8x

$8x = 3$

Solve for x

$x = \frac{3}{8}$

Solving (b): when x = 0

Substitute 0 for x

$g(x) = 3 - 8x$

$g(0) = 3 - 8 * 0$

$g(0) = 3 - 0$

$g(0) = 3$

Solving (c): When g(x) = -5

Substitute -5 for g(x)

$g(x) = 3 - 8x$

$-5 = 3 - 8x$

Solve for 8x

$8x = 3 + 5$

$8x = 8$

Solve for x

$x = \frac{8}{8}$

$x = 1$

Solving (d): When x = 3

Substitute 3 for x

$g(x) = 3 - 8x$

$g(3) = 3 - 8 * 3$

$g(3) = 3 - 24$

$g(3) = -21$

3 0

2 years ago

Please help me with this question.

mixas84 [53]

Answer:

B

Step-by-step explanation:

In a triangle, the sum of any two sides must be bigger than the third.

For the first one, 10+20=30 is not greater than 30, so this is not correct.

For B, 122+137 = 259 > 257, 257+137>122 , and 257 + 122 > 137. This works

For C, 8.6 + 2.7 = 11.3 < 12.2, so this does not work

For D, 1/6 + 1/5 = 5/(6*5) + 6/(6*5) = 5/30 + 6/30 = 11/30 < 1/2 = 15/30, so this does not work

7 0

2 years ago

Which of the following equations can be used to find the length of in the

ANEK [815]

The other leg will be LN² = 33² - 11². Then the correct option is A.

<h3>What is a Pythagoras theorem?</h3>

The Pythagoras theorem states that the sum of two squares equals the squared of the longest side.

The Pythagoras theorem formula is given as

H² = P² + B²

The hypotenuse is 33 units and one leg is 11 units.

Then the other leg will be

33² = LN² + 11²

LN² = 33² - 11²

Then the correct option is A.

More about the Pythagoras theorem link is given below.

brainly.com/question/343682

#SPJ1

3 0

1 year ago

the length of a rectangle is 24 units. can the perimeter x of the rectangle be 60 units when its width y is 11 units

S_A_V [24]

24 +24 = 48

11 + 11 = 22

48 +22 = 70

the perimeter cannot be 60 with dimensions of 24 & 11

5 0

3 years ago

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