1200/200 in a simplified form is
3/5
<span>We are given f(1) = 0 and f(2) = 1.
Going forward, the term is the sum of the two previous terms.
f(3) = f(2) + f(1) = 0 + 1 = 1.
f(4) = f(3) + f(2) = 1 + 1 = 2
f(5) = f(4) + f(3) = 2 + 1 = 3
This matches answer B.</span>
These are the steps, with their explanations and conclusions:
1) Draw two triangles: ΔRSP and ΔQSP.
2) Since PS is perpendicular to the segment RQ, ∠ RSP and ∠ QSP are equal to 90° (congruent).
3) Since S is the midpoint of the segment RQ, the two segments RS and SQ are congruent.
4) The segment SP is common to both ΔRSP and Δ QSP.
5) You have shown that the two triangles have two pair of equal sides and their angles included also equal, which is the postulate SAS: triangles are congruent if any pair of corresponding sides and their included angles are equal in both triangles.
Then, now you conclude that, since the two triangles are congruent, every pair of corresponding sides are congruent, and so the segments RP and PQ are congruent, which means that the distance from P to R is the same distance from P to Q, i.e. P is equidistant from points R and Q
Answer:
simple. quadrant III
Step-by-step explanation:
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Answer:
The measure of the arc PJ is 
Step-by-step explanation:
step 1
Find the measure of angle L
we know that
In a inscribed quadrilateral opposite angles are supplementary
so
we have
substitute
step 2
Find the measure of arc KJ
we know that
The inscribed angle measures half that of the arc comprising
so
substitute the values
step 3
Find the measure of arc PJ
we know that
The inscribed angle measures half that of the arc comprising
so
substitute the values
