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3 years ago

Which statement is true about the graphs of the two lines y = –6 and x =1/6 ?

Mathematics

2 answers:

sweet-ann [11.9K]3 years ago

6 0

These lines are perpendicular because y = -6 is a horizontal line with a slope of 0 and x = 6 is a vertical line with an undefined slope

lisabon 2012 [21]3 years ago

3 0

Answer:- The lines are perpendicular to each other because the graph of y = –6 is a horizontal line with a slope that is undefined, and the graph of x = 1/6 is a vertical line with a slope of 0.

Explanation:-

The x -axis is a horizontal line with the equation y=0. Its slope is 0

The y -axis is a horizontal line with the equation x=0 . Its slope is not defined.

y=-6 is a horizontal line and is parallel to x axis.

∴Its slope is 0. [slope of parallel lines are equal]

x=1/6 is a vertical line parallel to y-axis.

∴ Its slope not defined. [slope of parallel lines are equal]

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Read 2 more answers

Please answer 26 and 27 please thank you

ser-zykov [4K]

Answer:

Part 26) $3\frac{1}{4}\ in$

Part 27) $2\frac{2}{3}\ cups$

Step-by-step explanation:

Part 26)

we know that

The length of Alana's hair was 9 3/4 inches

After her haircut, the length was 6 1/2 inches

To find out how many inches did she have cut subtract 6 1/2 from 9 3/4

but first

Convert mixed number to an improper fraction

$9\frac{3}{4}\ in=\frac{9*4+3}{4}=\frac{39}{4}\ in$

$6\frac{1}{2}\ in=\frac{6*2+1}{2}=\frac{13}{2}\ in$

Find the difference

$\frac{39}{4}-\frac{13}{2}=\frac{39-26}{4}=\frac{13}{4}\ in$

Convert to mixed number

$\frac{13}{4}\ in=\frac{12}{4}+\frac{1}{4}=3\frac{1}{4}\ in$

Part 27)

we have that

Emeril used a total of 7 1/4 cups of flour to make three pastries

He used 2 1/4 cup of flour for the first and 2 1/3 cups of flour for the second

To find out how much cups of flour Emeril use for the third pastry, subtract the sum of the cups of flour used in the first and second pastry from the total cups of pastry used

Let

x ----> number of cups of flour used in the third pastry

$x=7\frac{1}{4}-(2\frac{1}{4} +2\frac{1}{3})$