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lesya [120]
3 years ago
6

A scientist is studying two traits in a type of beetle: body texture and color. Smooth body (B) is dominant to bumpy body (b), a

nd gray (G) is dominant to white (g). A BbGg and a bbgg beetle mate and produce the following offspring: Number of Offspring Phenotype 345 Smooth, gray355 Bumpy, white 188 Smooth, white152 Bumpy, grayWhat is the percent recombination frequency for this cross?
Biology
1 answer:
TEA [102]3 years ago
8 0

Answer:

32.692%

Explanation:

Recombination frequency= total number of recombinant phentoype in the population/ total population size x 100

The heterozygous parent BbGg would form two types of recombinant gametes and two types of parental gametes. The recombinant gametes would carry the allele Bg (smooth and white) and bG (bumpy and gray).

Total recombinant phenotypes in the given progeny= 188 Smooth, white + 152 Bumpy, gray= 188 + 152 = 340

Total population size= 345 Smooth, gray + 355 Bumpy, white + 188 Smooth, white + 152 Bumpy, gray = 345 + 355 + 188 + 152 = 1040

Recombination frequency= 340/1040 x 100 = 32.692%

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The correct answer is C. Translation.

The given figure is the scheme of the gene expression. It provides the flow of genetic information from a DNA sequence to a protein synthesis inside cells. This process of flow of genetic information from DNA to RNA is called transcription and the process of flow of genetic information from RNA to protein is called translation.

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A. Determine the surface area, volume, and surface area to volume ratio for the following three blocks. Then, state which one yo
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Explanation:

In a cell, the rate of diffusion is higher when the surface area to volume ratio is higher.  

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Volume ⇒ 1.5 cm x 1.5 cm x 1.5 cm= 3.375  cm^{3}

Surface area  ⇒ (1.5 cm x 1.5 cm x 1.5 cm) x 6=13.5   cm^{2}

Surface area :Volume  ⇒ \frac{13.5}{3.75}= 1:4

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Surface area  ⇒(2 (.5 cm x .5 cm)) + (4(.5 cm x 6 cm))= 0.5+12 = 12.5 cm^{2}

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Volume  ⇒3 cm x 2 cm x 2 cm= 12 cm^{3}

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Surface area :Volume  ⇒  \frac{42}{12}= 7:2

<em>The highest ratio is said to be the most efficient; with a higher surface area, more substances can pass across the surface of the cell at a time. </em>

<em />

Further Explanation:

Cells require all substances to cross the cell membrane. These, like agar, which contains small pores, is semi permeable -only allowing some molecules to pass cross the membrane or surface. The cubes contain a pH indicator that reacts with the solute, vinegar. Cell membranes contain lipids which form a barrier; polarity or arrangement can give these non-polar macromolecules hydrophilic and hydrophobic properties.

Via diffusion, small water molecules can move across the phospholipid bilayer acts as a semi-permeable membrane into the extracross the phospholipid bilayer acts as a semi-permeable membrane into the extracellular fluid or the cytoplasm which are both hydrophilic and contain large concentrations of polar water molecules or other water-soluble compounds. The hydrophilic heads of the bilayer are attracted to water while their water-repellent hydrophobic tails face towards each other- allowing molecules of water and water soluble molecules, to diffuse across the membrane along the concentration gradient

acellular fluid or the cytoplasm which are both hydrophilic and contain large concentrations of polar water molecules or other water-soluble compounds. The hydrophilic heads of the bilayer are attracted to water while their water-repellent hydrophobic tails face towards each other- allowing molecules of water and water soluble molecules, to diffuse across the membrane along the concentration gradient

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Learn more about membrane components at brainly.com/question/1971706

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#LearnWithBrainly

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