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kiruha [24]
3 years ago
6

Which of the following is an odd function?

Mathematics
1 answer:
madreJ [45]3 years ago
7 0

Answer:

Step-by-step explanation:

f(x) = x is an odd function; the power of x is x^1.

f(x) = -x is also an odd function.

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Slope intercept form that passes though the point (-2,-3) and has a slope of 5/2
olganol [36]

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8 0
3 years ago
Read 2 more answers
Given the diagram below. If G is the circumcenter of ABC. DC = 16, GB = 21 and AZ = 19, find each measure.​
Jlenok [28]

Answer:

Step-by-step explanation:

Properties of a circumcenter;

1). Circumcenter of a triangle is a point which is equidistant from all vertices.

2). Point where perpendicular bisectors of the sides of a triangle meet is called circumcenter of the triangle.

From the picture attached,

9). AG = GB = GC = 21

10). BC = 2(DC)

            = 2×16

            = 32

11). By applying Pythagoras Theorem in ΔGFB,

     GB² = GF² + FB²

     (21)² = GF² + (19)²

     441 = GF² + 361

     GF² = 441 - 361

     GF = \sqrt{80}

     GF = 8.9

12). By applying Pythagoras theorem in ΔGDB,

     GB² = DG² + BD²

     (21)² = (DG)² + (16)² [BD = DC = 16]

     DG² = 441 - 256

     DG = √185

     DG =  13.6

7 0
3 years ago
If the degree for the polynomial function f(x) is 7 and below is the graph of f(x), then how many zeroes are there total? How ma
yanalaym [24]
There would be 1 cause
8 0
3 years ago
Select all sets of lengths that would form a right triangle.
VARVARA [1.3K]

Answer:

theres no picture ill still answer if you put a picture or somthing of the triangle

Step-by-step explanation:

3 0
3 years ago
Determine if the given ordered pairs are solution of x+ 4y = 7.
const2013 [10]

Answer:

(3, 1 ) is a solution

Step-by-step explanation:

To determine if the given points are solutions, substitute the x and y values into the left side of the equation and if equal to the right side then they are solutions.

(3, 1 )

3 + 4(1) = 3 + 4 = 7 = right side , then a solution

(2, 1 )

2 + 4(1) = 2 + 4 = 6 ≠ 7 ← not a solution

6 0
3 years ago
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