Question

What is an equation of circle O shown in the graph below?

Answer 1

Answer:

Equation of circle is $x^2+y^2-12x-4y+24=0$

None of the options is correct

Step-by-step explanation:

Given: Graph

To find: equation of circle

Solution:

A circle is a locus of all points that are at a fixed distance (radius) from a fixed point (centre).

From the graph,

centre (a, b) = $\left ( 6,2 \right )$

radius (r) = 4 units

Equation of circle is of form $(x-a)^2+(y-b)^2=r^2$

$(x-6)^2+(y-2)^2=4^2\\x^2+36-12x+y^2+4-4y=16\\x^2+y^2-12x-4y+24=0$