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marin [14]
3 years ago
12

2+2/////////............................................

Mathematics
2 answers:
melisa1 [442]3 years ago
4 0

Answer:

2+2=4

Step-by-step explanation:

so i hope this helped

Nat2105 [25]3 years ago
3 0
2+2 = 4
hope i helped you today.
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|x+6| =8 <br> A) x=-2 and x= -14<br> B) x= -2 and x= 14 <br> C) x=2 and x= -14 <br> D) x=2 and x= -2
erica [24]

Answer:

C) x=2 and x= -14

Step-by-step explanation:

|x + 6| = 8

means

x + 6 = 8 or x + 6 = -8

x + 6 = 8

x = 2

x + 6 = -8

x = -14

5 0
3 years ago
What is the scale factor of the dilation when the pre-image is 9 and the image is 24?​
lakkis [162]
<h3>Answer:  8/3</h3>

Explanation:

Divide the image length over the pre-image length to get

24/9 = (8*3)/(3*3) = 8/3

The scale factor is 8/3. This means the image is 8/3 times longer compared to the pre-image.

6 0
3 years ago
Lsplslsplpsplslpsllspslpslpslpslpsplspslpslpslpslpslsplsplspls
Ivan

Answer:

257.61

Step-by-step explanation:

FORMULA=  C=2πr=2·π·41≈257.6106

there is a screenshot included too

6 0
3 years ago
Read 2 more answers
Suppose that two teams are playing a series of games, each of which is independently won by team A with probability p and by tea
Lady_Fox [76]

Answer:

4 games played = 1/56

5 games played = 5/56

6 games played = 15/56

7 games played = 35/56

Step-by-step explanation:

The probability of each time winning is 0.5

So there are a couple of ways the series could go.

  1. Team A could win all first 4 matches. We can depict this as A-A-A-A
  2. Team A could win 4, while having lost 1.  Lets depict this a A-B-A-A-A
  3. Team A could win 4, while having lost 2. A-B-B-A-A-A
  4. Team A could win 4, while having lost 3. A-B-B-B-A-A-A

These 4 possibilities could be repeated with B winning as well. It should be noted that these are the only ways for the series to end. We find the number of permutations of each possibility above to find their probability.

I advise you to study 'how to permute identical objects' for this.

These permutations are stated below:

1. 4!/4! = 1

2. \frac{5!}{4! * 1!} = 5

3 \frac{6!}{4! * 2!} = 15

4 \frac{7!}{4! * 3!} = 35

These are they ways A or B could win. The total is 1+5+15+35 = 56. The answer given thus reflects the possibilities.

4 0
4 years ago
Plz help I have to bring this homework for tomorrow plz some one help
Simora [160]
The snacks that more girls chose than boys are the Nuts and the Fruit Bar

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7 0
4 years ago
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