Answer: A. We will divide total seeds by the number of total rows.
300 seeds will be planted in each row.
Step-by-step explanation:
Given: Total seeds = 2700
Total rows = 9
If each row will have the same number of seeds.
Then, the number of seeds will be planted in each row = (Total seeds) ÷ (Total rows)
= 2700÷9
= 300
Hence, 300 seeds will be planted in each row.
90 mins bc 120/8=x/6 so cross multiply
Whenever you multiply or divide a negative number to both sides, you flip the sign
ex.
if you have x>1, and multiply -1 to both sides, then -x <-1
in your case, the best way to remove the -2 from the denominator would be to multiply -2 to both sides. Since you multiplied by a negative number, you need to switch the sign from < to >
The number of terms in the given arithmetic sequence is n = 10. Using the given first, last term, and the common difference of the arithmetic sequence, the required value is calculated.
<h3>What is the nth term of an arithmetic sequence?</h3>
The general form of the nth term of an arithmetic sequence is
an = a1 + (n - 1)d
Where,
a1 - first term
n - number of terms in the sequence
d - the common difference
<h3>Calculation:</h3>
The given sequence is an arithmetic sequence.
First term a1 =
= 3/2
Last term an =
= 5/2
Common difference d = 1/9
From the general formula,
an = a1 + (n - 1)d
On substituting,
5/2 = 3/2 + (n - 1)1/9
⇒ (n - 1)1/9 = 5/2 - 3/2
⇒ (n - 1)1/9 = 1
⇒ n - 1 = 9
⇒ n = 9 + 1
∴ n = 10
Thus, there are 10 terms in the given arithmetic sequence.
learn more about the arithmetic sequence here:
brainly.com/question/503167
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Disclaimer: The given question in the portal is incorrect. Here is the correct question.
Question: If the first and the last term of an arithmetic progression with a common difference are
,
and 1/9 respectively, how many terms has the sequence?
Answer:
horizontal
Step-by-step explanation: