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never [62]
3 years ago
8

A farmer has 18 animals (cows and chickens). He counts 60 legs. How many chickens does he have?

Mathematics
2 answers:
Leona [35]3 years ago
5 0
Chickens have 2 legs and cows have 4
algol [13]3 years ago
5 0
To do this problem, you have to make what is called a "system of equations" (2 related equations). One will relate to the number of chickens and cows, the other will relate to the numbers of legs. But in both equations, the variables "x" and "y"  will be the number of cows (x) and number of chickens (y)

You know that the farmer has 18 total animals, so x + y = 18.
You know that cows have 4 legs and chickens have 2 legs, and the 18 cows and chickens have 60 legs total, so 4x + 2y = 60.

Now, to "solve" the system of equations, you can take the simpler equation x+y = 18, and simplify it, to stand in for variables.
Since we want to find y, the number of chickens, let's make this equation = x.
So, it is now x = 18 - y.

Now you can take 18-x and put it into the OTHER equation to stand in for y, so that you can solve for y.

4(18-y) + 2y = 60

Distribute around the parentheses...

72 - 4y + 2y = 60

Combine the y's.

72 - 2y = 60

-72 from both sides

-2y = -12

Divide by -2!

y = 6

So, there are 6 chickens.

And, if you wanted to find the number of cows, you can plug the value for y into the equation again... 6 + x = 18 and solve for x.

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Alinewithaslopeof7passesthroughthepoint
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3 years ago
How many terms of the series of - 3+0+3+6+9+...are needed to give a sum of 105?​
dolphi86 [110]

Answer:

10

Step-by-step explanation:

Remember that the formula for the sum of an arithmetic series is:

S=\frac{k}{2}(a+x_k)

Where k is the number of terms, a is the initial term, and x_k is the last term of the series.

We essentially want to find k, the number of terms, given that the sum S is equal to 105. So, substitute 105 into our equation:

105=\frac{k}{2}(a+x_k)

To do so, we need to final term x_k. We don't know what it is yet, but that doesn't matter. All we need to do is to write it in terms of k. First, remember that the standard form for the explicit formula of an arithmetic sequence is:

x_n=a+d(n-1)

Where a is the first term, d is the common difference, and n is the nth term.

From our sequence, we can see that the first term is -3.

Also, we can determine that our common difference is +3, since each subsequent term is 3 <em>more</em> than the previous one. -3+3 is 0, 0+3 is 3, 3+3 is 6, and so on.

Therefore, our explicit formula is:

x_n=-3+3(n-1)

Therefore, our final term, x_k, will be if we substitute k for n. So, we can acquire the equation:

x_k=-3+3(k-1)

Now that we know what x_k is, we can substitute that into our original equation:

105=\frac{k}{2}(a+x_k)

Substitute the equation into x_k. Also, let's substitute -3 (our first term) for a. So:

105=\frac{k}{2}(-3+(-3+3(k-1)))

And now, all we have to do is to solve for k.

First, distribute the 3:

105=\frac{k}{2}(-3+(-3+3k-3))

Add within the parentheses:

105=\frac{k}{2}(3k-9)

Multiply both sides by 2. This removes the fraction on the right:

210=k(3k-9)

Distribute. We will get a quadratic:

210=3k^2-9k

So, let's solve for k. Let's divide everything by 3:

70=k^2-3k

Subtract 70 from both sides:

0=k^2-3k-70

Factor. We can use -10 and 7. So:

0=(k-10)(k+7)

Zero Product Property:

k-10=0\text{ or } k+7=0

Solve for k for each equation:

k=10\text{ or } k=-7

-7 doesn't make sense (we can't have -7 terms). Remove that solution. So, we are left with:

k=10

Therefore, the number of terms we have in our series for our sum to be 105 is 10.

And we're done!

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3 years ago
Evaluate the expression<br> x+y3/5+ x²y when x = 3 and y = -2
olga55 [171]
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I plugged in the calculator for you:)
8 0
3 years ago
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