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miss Akunina [59]
3 years ago
8

2/2 - 7x-4 Simplify - 58+4 2x + 1 2-1 2x + 1 *+1 2-72

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
5 0

Answer:

A or (2x+1)/(x-1)

Step-by-step explanation:

Let's simplify the top of the fraction first.

1. Simplify the numerator.

2x^2 -7x-4=(2x+1)(x-4)

2. Simplify the denominator.

x^2-5x+4=(x-4)(x-1)

Now we have:

((2x+1)(x-4))/((x-4)(x-1))

We see that there is an (x-4) both on the numerator and denominator.

We can remove (x-4) by division.

Doing that, we have:

(2x+1)/(x-1) or A

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I will mark brainliest
butalik [34]

Answer: 16875

Step-by-step explanation:

Let the price of the washing machine be x.

Since she loses 20% in the bargain, this implies that she sold it at (100% - 20%) = 80%.

Therefore, 80% of x = 13500

0.8 × x = 13500

0.8x = 13500

Divide both side by 0.8

0.8x/0.8 = 13500/0.8

x = 16875

Therefore, the price at which she bought the washing machine is 16875 rupees.

6 0
2 years ago
Read 2 more answers
Write the word sentence as an inequality.<br><br> A number x minus 1/4 is no more than -3/4
Umnica [9.8K]

Answer:

x-1/4 ≤-3/4

Step-by-step explanation:

A number x

x

minus 1/4

x-1/4

is no more than   (it cannot be greater than , but it can be equal to)

x-1/4 ≤

-3/4

x-1/4 ≤-3/4

6 0
3 years ago
Can someone please help me out!!?
HACTEHA [7]

Answer:

x = 7

Step-by-step explanation:

\frac{10}{8} = \frac{3x-6}{12} --> Triangle Similarity Theorem

120 = 8(3x - 6) --> Cross Multiplying

120 = 24x - 48 --> Distributing the 8

24x - 48 + 48 = 120 + 48 --> Adding 48 on both sides

24x = 168 --> Simplifying

24x/24 = 168/24 --> Divide 24 on both sides

x = 7 --> Simplifying

Hope this helped! <3

8 0
3 years ago
A grocer mixed nuts worth 80 cents per pound with nuts worth 50 cents per pound. how many pounds of each did he use to make a mi
quester [9]
30 pounds to sell at .65 cents per pound
5 0
3 years ago
A car radiator needs a 80% antifreeze solution. The radiator now holds 15 liters of a 70% solutions. How many liters of this sho
slavikrds [6]
So... the radiator has 15 liters of 70% antifreeze.. but needs an 80% antifreeze

well, so, you need to drain some and put some with higher percentage, seems to be, you will end up at the same 15 liters, possible the radiator's capacity, of 80% antifreeze

so, the same amount going out, of 70% is the same amount going in, of 100% antifreeze

now.. let's use the decimal format for the percents, or 70% is 70/100 or 0.7 and so on
\bf \begin{array}{lccclll}&#10;&amount&concentration&&#10;\begin{array}{llll}&#10;concentration\\&#10;amount&#10;\end{array}\\&#10;&-----&-------&-------\\&#10;\textit{70\% sol'n, out}&x&0.7&0.7x\\&#10;\textit{100\% sol'n, in}&x&1.00&x\\&#10;\textit{current 70\% sol'n}&15&0.7&10.5\\&#10;-----&-----&-------&-------\\&#10;mixture&15&0.8&12&#10;\end{array}

so.. let's subtract, from the current solution, 0.7x and add 1x or x, our antifreeze concentration amount, should be 12 though

10.5 - 0.7x + x = 12

solve for "x"

3 0
3 years ago
Read 2 more answers
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