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Tresset [83]
3 years ago
13

Suppose your annual starting salary is $55,183. After working for a few years, you start to get yearly raises. If you get a 0.6%

raise a total of 3 times and then a 1.9% raise a total of 6 times, what is your salary after all the raises? Round your answer to the nearest dollar.
Mathematics
1 answer:
Marianna [84]3 years ago
4 0

Answer:

The salary after all the increment = $62899.0879

Step-by-step explanation:

It is given that starting annual salary = $55183

There is given that there are there are three time increment of 0.6 %

So salary after 0.6% increment of 3 times = 55183\times (1+\frac{0.6}{100})^3 = $56182.2656

After that there is other increment of 1.9 % that is 6 times

So salary after this increment = 56182.2656\times (1+\frac{1.9}{100})^6=62899.0879

So the salary after all the increment = $62899.0879

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Evaluate the double integral.
Fynjy0 [20]

Answer:

\iint_D 8y^2 \ dA = \dfrac{88}{3}

Step-by-step explanation:

The equation of the line through the point (x_o,y_o) & (x_1,y_1) can be represented by:

y-y_o = m(x - x_o)

Making m the subject;

m = \dfrac{y_1 - y_0}{x_1-x_0}

∴

we need to carry out the equation of the line through (0,1) and (1,2)

i.e

y - 1 = m(x - 0)

y - 1 = mx

where;

m= \dfrac{2-1}{1-0}

m = 1

Thus;

y - 1 = (1)x

y - 1 = x ---- (1)

The equation of the line through (1,2) & (4,1) is:

y -2 = m (x - 1)

where;

m = \dfrac{1-2}{4-1}

m = \dfrac{-1}{3}

∴

y-2 = -\dfrac{1}{3}(x-1)

-3(y-2) = x - 1

-3y + 6 = x - 1

x = -3y + 7

Thus: for equation of two lines

x = y - 1

x = -3y + 7

i.e.

y - 1 = -3y + 7

y + 3y = 1 + 7

4y = 8

y = 2

Now, y ranges from 1 → 2 & x ranges from y - 1 to -3y + 7

∴

\iint_D 8y^2 \ dA = \int^2_1 \int ^{-3y+7}_{y-1} \ 8y^2 \ dxdy

\iint_D 8y^2 \ dA =8 \int^2_1 \int ^{-3y+7}_{y-1} \ y^2 \ dxdy

\iint_D 8y^2 \ dA =8 \int^2_1  \bigg ( \int^{-3y+7}_{y-1} \ dx \bigg)   dy

\iint_D 8y^2 \ dA =8 \int^2_1  \bigg ( [xy^2]^{-3y+7}_{y-1} \bigg ) \ dy

\iint_D 8y^2 \ dA =8 \int^2_1  \bigg ( [y^2(-3y+7-y+1)]\bigg ) \ dy

\iint_D 8y^2 \ dA =8 \int^2_1  \bigg ([y^2(-4y+8)] \bigg ) \ dy

\iint_D 8y^2 \ dA =8 \int^2_1  \bigg ( -4y^3+8y^2 \bigg ) \ dy

\iint_D 8y^2 \ dA =8 \bigg [\dfrac{ -4y^4}{4}+\dfrac{8y^3}{3} \bigg ]^2_1

\iint_D 8y^2 \ dA =8 \bigg [ -y^4+\dfrac{8y^3}{3} \bigg ]^2_1

\iint_D 8y^2 \ dA =8 \bigg [ -2^4+\dfrac{8(2)^3}{3} + 1^4- \dfrac{8\times (1)^3}{3}\bigg]

\iint_D 8y^2 \ dA =8 \bigg [ -16+\dfrac{64}{3} + 1- \dfrac{8}{3}\bigg]

\iint_D 8y^2 \ dA =8 \bigg [ -15+ \dfrac{64-8}{3}\bigg]

\iint_D 8y^2 \ dA =8 \bigg [ -15+ \dfrac{56}{3}\bigg]

\iint_D 8y^2 \ dA =8 \bigg [  \dfrac{-45+56}{3}\bigg]

\iint_D 8y^2 \ dA =8 \bigg [  \dfrac{11}{3}\bigg]

\iint_D 8y^2 \ dA = \dfrac{88}{3}

4 0
2 years ago
When Brad was born, his Grandma put, $1,500 in a new account for him. Since then, the balance of the account, has grown by 6.5%
marin [14]

Answer:

$969.04

Step-by-step explanation:

now at age of 18 Brad has 1500 * 1,065^18

at age of 21 he will have 1500 * 1,065^21

if he waits the difference will be 1500 * 1,065^21 - 1500 * 1,065^18 = $969.04

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3 years ago
My teacher won't help i I actually want to learn this can you please help me​
Reika [66]
15 you have to do all the steps thank it this I think
6 0
3 years ago
Find the value of x.​
Vika [28.1K]

Answer:

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7 0
2 years ago
Please help me!! Il give u brainliest(:
baherus [9]

Answer: f^-1(x)= 2-4x/3

This is because the power of f is -1

7 0
3 years ago
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