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chubhunter [2.5K]
3 years ago
14

Solve the equation. Show the steps of the solution process. Solve: -14 = -3(6 + 6k) + 4

Mathematics
2 answers:
Murljashka [212]3 years ago
7 0

Answer:

very easy just simplify and solve

Step-by-step

k=0

svp [43]3 years ago
3 0
K=0

Best luck with your studying

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Find the slope on the line ​
julsineya [31]

Answer:

slope is -3

Step-by-step explanation:

change in y over change in x is -3/1

6 0
3 years ago
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Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

  • J(2;5); K(1;1)

             => JK = \sqrt{(1-2)^{2} + (1-5)^{2}  } = \sqrt{(-1)^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • J(2;5); L(5;2)

             => JL = \sqrt{(5-2)^{2} + (2-5)^{2}  } = \sqrt{3^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • K(1;1); L(5;2)

             =>  KL = \sqrt{(5-1)^{2} + (2-1)^{2}  } = \sqrt{4^{2}+1^{2}  } = \sqrt{1+16}=\sqrt{17}

In the triangle QNP, the sides can be calculate as following:

  • Q(-4;4); N(-3;0)

             => QN = \sqrt{[-3-(-4)]^{2} + (0-4)^{2}  } = \sqrt{1^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • Q (-4;4); P(-7;1)

   => QP = \sqrt{[-7-(-4)]^{2} + (1-4)^{2}  } = \sqrt{(-3)^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • N(-3;0); P(-7;1)

             =>  NP = \sqrt{[-7-(-3)]^{2} + (1-0)^{2}  } = \sqrt{(-4)^{2}+1^{2}  } = \sqrt{16+1}=\sqrt{17}

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0
3 years ago
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Find the commission 690.48
skad [1K]

Answer:

more information would love to help

Step-by-step explanation:

3 0
3 years ago
Pls help LOL I need helo
Andrews [41]
500$ if that’s an answer
5 0
2 years ago
Due tomorrow please help
NeX [460]
For some of these, a calculator is helpul.

The sum is 294903.

_____
This is the sum of 15 terms of a geometric sequence with first term 9 and common ratio 2. That sum is given by the formula
S_{n}=a\dfrac{r^{n}-1}{r-1}
S_{15}=9\dfrac{2^{15}-1}{2-1}=9\cdot(32768-1)=294903

7 0
3 years ago
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