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sweet [91]
3 years ago
8

If (x+8) is a factor of f(x), which of the following must be true?

Mathematics
2 answers:
Helga [31]3 years ago
8 0

Answer:

C

Step-by-step explanation:

Given that (x + 8) is a factor of f(x), then x = - 8 is a root and thus

f(- 8) = 0

natulia [17]3 years ago
8 0

Answer:

Excellent! The correct answer is C. (3rd option) got my test right!

Step-by-step explanation:

Thank you! ;)

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I need help wit one & two please help
seropon [69]

23 is less than 25 which means it's closer to 20, so you would round it down to 20. 1.75 is over 0.50, 1/2, so you would round it up to 2. If you multiply 2 and 20 you would get 40.

Number two gets the same explanation just with different numbers.

3 0
3 years ago
You have two summer jobs. At the Burger Palace you earn $8 per hour. At the community center you teach soccer clinics for $10 pe
SIZIF [17.4K]
The complete question in the attached figure
 we have that
x-------------> number of hours works at Burger Palace -----> <span>$8
</span>y-------------> number of hours works at <span>community center</span> -----> $10
<span>
8x+10y>=200

using a graph tool
see the attached figure

the answer is the option B
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8 0
3 years ago
What are the correct justifications , listed in proper order?
Sergio039 [100]

Answer:

4 5 6 7

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle? A) (x
Andrei [34K]

Answer:

\large\boxed{A.\ (x+6)^2+(y+10)^2=20}

Step-by-step explanation:

The standard form of an equation of a circle:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the endpoints of the diameter of a circle (-8, -6) and (-4, -14).

The midpoint of a diameter is a center of a circle.

The formula of a midpoint:

\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)

Substitute:

x=\dfrac{-8+(-4)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{-6+(-14)}{2}=\dfrac{-20}{2}=-10

We have h = -6 and k = -10.

The radius is the distance between a center and the point on a circumference of a circle.

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute (-6, -10) and (-8, -6):

r=\sqrt{(-8-(-6))^2+(-6-(-10))^2}=\sqrt{(-2)^2+4^2}=\sqrt{4+16}=\sqrt{20}

Finally we have

(x-(-6))^2+(y-(-10))^2=(\sqrt{20})^2\\\\(x+6)^2+(y+10)^2=20

5 0
3 years ago
Read 2 more answers
Triangle DEF is isosceles, where . Angle FDE is bisected by segment DG, creating angle GDE with a measure of 29°. What is the me
schepotkina [342]
Isosceles - two sides equal 

2 angels the same 
 
29 + 29 = 58 

180 - 58 = 122

122 = DFE 
5 0
3 years ago
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