Question

If g(x)=7x²−4x−3 and h(x)=5x²−12x, find (h∘g)(1)FIRST BEST ANSWER BRAINLIEST

Answer 1

Answer: See below

Step-by-step explanation:

$h\:\circ \:g=h\left(g\left(x\right)\right)$

$=5\left(7x^2-4x-3\right)^2-12\left(7x^2-4x-3\right)$

$=5\left(7x^2-4x-3\right)\left(7x^2-4x-3\right)-12\left(7x^2-4x-3\right)$

$=245x^4-280x^3-130x^2+120x+45-84x^2+48x+36$

Simplify:

$=245x^4-280x^3-214x^2+168x+81$