Question

X+y=32x-y=3 using elimination method​

Answer 1

X=2, y=1 plug it in and it works
By elimination the y cancels itself out and then you add 2x+x to get 3x, add 3+3 and get 6. If 3x = 6, then divide by 3 and you get x=2. If you put that in the first equation, 2 +y= 3, it is obvious that y equals 1.

Answer 2

Answer:

x = 2 , y=1

Step-by-step explanation:

to solve the equation using elimination method we say

let

x+y=3 .................. equation 1

2x-y=3................ equation 2

add all the equation together inorder to get rid of y

we have

  x + y = 3

+ 2x -y = 3

------------------------

3x = 6

divide both sides by 3

3x/3 = 6/3

x = 2

substitute for x = 2 in equation 1 to get the value of y

x+y=3 .................. equation 1

2 + y = 3

y = 3 -1

y =2

therefore the value of x and y is 2 & 1 respectively