Answer:
1/4 suffer from hemophilia
1/4 are heterozygous
Explanation:
So since they are normal but their son isn't it is assumed that the mom is the carrier since the dad has to be X^HY
X^HY x X^HX^h
Set up a pedigree
X^HX^H X^HX^h
X^HY X^hY
1/4 suffer from hemophilia (X^h)
1/4 are heterozygous (X^HX^h)
Answer:
A. Molecular changes such as extracellular signals on extracellular ligands can result in quick changes in cell behaviour. One example is insulin. Upon insulin binding on the receptor on the cell membrane, the cell release GLUT4 transporters (for muscle cells) to increase uptake of glucose.
B. Slow changes in cell behaviour can be observed for other lipophilic hormones or intracellular receptors such as glucocoortoid or estrogen which reacts with receptors in the cells.
C. Insulin is required to maintain a constant blood glucose level and hence levels of insulin has to be mediated in correspondence to the blood glucose levels. Fast acting signalling is thus required for homeostasis of blood glucose levels. Where for such lipophilic hormones such as steriods, glucocortoid, these hormones tend to have a longer lasting effect and hence results in a slow change.
Hey friend!
Let's figure this out
Fragmental sedimentary rocks include shale, sandstone, conglomerate, <span>salt, </span><span>breccia, </span><span>limestone, </span><span>chert, </span><span>dolomite, coal, </span><span><span>siltstone, and gypsum.
As you can see, Gneiss is not listed among examples of fragmental sedimentary rock. So your answer is B.
Hope this helps!</span></span>
Answer:
D. Limit further logging and clearcutting of pine trees.
Explanation:
photovoltaic cell convert light energy in semiconductor
