Answer:
(1, 2)
Step-by-step explanation:
x2-x1/2, y2-y1/2
Plug in the values, and you should get (1, 2)
Answer:
The answer is below
Step-by-step explanation:
The question is not complete, the correct question is:
If B is between A and C, and AB=3x+1, BC=2x-7, and AC=24, then find the value of x and the value of AB
Answer: The line segment addition postulate states that if a point B is placed between a line segment with end points A and C, then the distance between the points can be expressed by the equation:
AB + BC = AC
But AB=3x+1, BC=2x-7, and AC=24, Hence:
3x + 1 + 2x - 7 = 24
3x + 2x + 1 - 7 = 24
5x - 6 = 24
5x = 24 + 6
5x = 30
x = 6
AB = 3x + 1 = 3(6) + 1 = 18 + 1 = 19
BC = 2x - 7 = 2(6) - 7 = 12 - 7 = 5
Answer:
See below ~
Step-by-step explanation:
Given :
⇒ m∠1 = m∠2
⇒ HD = GF
=============================================================
To Prove :
<u>Δ EHD ≅ Δ EGF</u>
<u />
============================================================
Solving :
⇒ m∠1 = m∠2 (Given)
⇒ HD = GF (Given)
⇒ ∠E = ∠E (Common angle)
⇒ ΔEHD ≅ ΔEGF (AAS congruence)
Answer:
A, C
Step-by-step explanation:
Actually, those questions require us to develop those equations to derive into trigonometrical equations so that we can unveil them or not. Doing it only two alternatives, the other ones will not result in Trigonometrical Identities.
Examining
A) True

Double angle 
B) False,
No further development towards a Trig Identity
C) True
Double Angle Sine Formula 

D) False No further development towards a Trig Identity
![[sin(x)-cos(x)]^{2} =1+sin(2x)\\ sin^{2} (x)-2sin(x)cos(x)+cos^{2}x=1+2sinxcosx\\ \\sin^{2} (x)+cos^{2}x=1+4sin(x)cos(x)](https://tex.z-dn.net/?f=%5Bsin%28x%29-cos%28x%29%5D%5E%7B2%7D%20%3D1%2Bsin%282x%29%5C%5C%20sin%5E%7B2%7D%20%28x%29-2sin%28x%29cos%28x%29%2Bcos%5E%7B2%7Dx%3D1%2B2sinxcosx%5C%5C%20%5C%5Csin%5E%7B2%7D%20%28x%29%2Bcos%5E%7B2%7Dx%3D1%2B4sin%28x%29cos%28x%29)
Answer: 11/14, also known as eleven fourteenths
Step-by-step explanation:
Hope this helped ! :)