The coordinates of the vertex that A maps to after Daniel's reflections are (3, 4) and the coordinates of the vertex that A maps to after Zachary's reflections are (3, 2)
<h3>How to determine the coordinates of the vertex that A maps to after the two reflections?</h3>
From the given figure, the coordinate of the vertex A is represented as:
A = (-5, 2)
<u>The coordinates of the vertex that A maps to after Daniel's reflections</u>
The rule of reflection across the line x = -1 is
(x, y) ⇒ (-x - 2, y)
So, we have:
A' = (5 - 2, 2)
Evaluate the difference
A' = (3, 2)
The rule of reflection across the line y = 2 is
(x, y) ⇒ (x, -y + 4)
So, we have:
A'' = (3, -2 + 4)
Evaluate the difference
A'' = (3, 4)
Hence, the coordinates of the vertex that A maps to after Daniel's reflections are (3, 4)
<u>The coordinates of the vertex that A maps to after Zachary's reflections</u>
The rule of reflection across the line y = 2 is
(x, y) ⇒ (x, -y + 4)
So, we have:
A' = (-5, -2 + 4)
Evaluate the difference
A' = (-5, 2)
The rule of reflection across the line x = -1 is
(x, y) ⇒ (-x - 2, y)
So, we have:
A'' = (5 - 2, 2)
Evaluate the difference
A'' = (3, 2)
Hence, the coordinates of the vertex that A maps to after Zachary's reflections are (3, 2)
Read more about reflection at:
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You’re right, it’s just 100/25.
Answer:
Answer
Step-by-step explanation:
300-28= g x 7
Answer:
C. 1/(x^2 +1) > 0
Step-by-step explanation:
The cube of a negative number is negative, eliminating choices B and D for certain negative values of x.
1/x^2 is undefined for x=0, so cannot be compared to zero.
The value 1/(x^2+1) is positive everywhere, so that is the expression you're looking for.
1/(x^2 +1) > 0
Given:
The values are 
.
To find:
The values of 
and 
.
Solution:
We have,
...(i)
Multiply both sides by 10.
...(ii)
Subtracting (i) from (ii), we get
And,
Now, the product of a and b is:
The quotient of a and b is:
Therefore, the required values are and .
