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3 years ago

9

Katie uses a copy machine to enlarge her rectangular design that is 6in wide and 8in long. The new width is 10in. What is the ne

w length?

2 answers:

Marysya12 [62]3 years ago

8 0

Your answer to your question would be 12. HOPE THIS HELPS! :^

Liono4ka [1.6K]3 years ago

5 0

The length is approximately 13 inches long.

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A sector with an area of 11/2 pie cm has radius of 3 cm what is the central angle measure of a sector in degrees

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A= 1/360 m•pi r^2

11/2= 1/360 m• pi (3)^2

11/2= 1/360 m• pi • 9
Divide 360 by 9

11/2= 1/40 m pi

Cross multiply

440=2pi m

Divide both sides by 2pi

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3 years ago

A mathematics teacher wanted to see the correlation between test scores and

SpyIntel [72]

Answer:

The homework grade, to the nearest integer, for a student with a test grade of 68 is 69.

Step-by-step explanation:

The general form of the linear regression equation is:

$y=a+bx$

Here,

<em>y</em> = dependent variable = test grade

<em>x</em> = independent variable = homework grade

<em>a</em> = intercept

<em>b</em> = slope

Compute the value of <em>a</em> and <em>b</em> as follows:

$a=\frac{\sum Y\cdot \sum X^{2}-\sum X\cdot\sum XY}{n\cdot \sum X^{2}-(\sum X)^{2}}\\\\=\frac{(592\times 44909)-(591\times45227)}{(8\times44909)-(591)^{2}}\\\\=-14.316$ $b=\frac{n\cdot \sum XY-\sum X\cdot\sum Y}{n\cdot \sum X^{2}-(\sum X)^{2}}\\\\=\frac{(8\times 45227)-(591\592)}{(8\times44909)-(591)^{2}}\\\\=1.195$

The linear regression equation that represents the set of data is:

$y=-14.316+1.195x$

Compute the value of <em>x</em> for <em>y</em> = 68 as follows:

$y=-14.316+1.195x$

$68=-14.316+1.195x\\1.195x=68+14.316\\1.195x=82.316\\x=68.884\\x\approx 69$

Thus, the homework grade, to the nearest integer, for a student with a test grade of 68 is 69.

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3 years ago

The orbital period, P, of a planet and the planet’s distance from the sun, a, in astronomical units is related by the formula P=

Elodia [21]

Answer: 9.54731702 astronomical units

Step-by-step explanation:

Given: The orbital period, P, of a planet and the planet’s distance from the sun, a, in astronomical units is related by the formula $P=a^{\frac{3}{2}$ .

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Substitute this value in the equation above, we get

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Hence, its distance from the sun = 9.54731702 astronomical units.

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3 years ago

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