Answer:
I know looks confusing
Step-by-step explanation:
f(1)=35f(n)=f(n−1)−2f(2)=f(1)−2=35−2=33f(3)=f(2)−2=33−2=31f(4)=f(3)−2=31−2=29f(5)=f(4)−2=29−2=27
Answer: 35, 33, 31, 29, 27.
Answer:
That would be :
4x – 10 = x2 – 5x + 10 ( y = 4x - 10 is substitute for y)
PROOF: y + 5x = x² + 10
(4x - 10) + 5x = x² + 10
4x - 10 = x² -5x + 10
0 = x2 – 9x + 20 (liked terms are grouped and simplified)
PROOF: 4x - 10 = x² -5x + 10
4x = x² -5x + 10 + 10
0 = x² -5x -4x + 20
0 = x² - 9x + 20
Solving:
x² - 9x + 20 = 0
x² - 5x - 4x + 20 = 0
(x - 5) (x - 4) = 0
⇒ x = 4 (as question says) OR x = 5
Step-by-step explanation:
hope this helps
The rule to use is PEMDAS. (Parenthesis, Exponents, Multiplication, Division, Addition, and Subtraction) When there's a number in front of one parenthesis, you distribute that number to the terms on the inside based on PEMDAS. What should also be notified is the exponent rules for multiplication and division. Then combine like terms. They have to have the same base of multiplying or dividing. Combining like terms need to have the same exponent, or whole numbers in groups.
Answer:
B. Number the students on the school roster. Use a table of random numbers to choose 160 students from this roster for the survey.
Step-by-step explanation:
