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3 years ago

Determine which of these illustrates two quantities that combine to make 0.

Mathematics

1 answer:

Butoxors [25]3 years ago

6 0

I think it’s gonna be D

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Yin min owns A small store the first month store was open she made 1375 in profit during the next month she advertising local ne

PilotLPTM [1.2K]

Hey there! As far as I understand the problem, she made $2,200 in profit. Take 1,375 and multiply it by 1.6.

6 0

3 years ago

You are given a cell phone bill. You are charged $52 for the month. There is a $40 monthly fee and you are charged $4 per megab

Mice21 [21]

The equation for the problem is y = 4x + 40. The slope is 4 and the y intercept is 40

The standard equation for a linear equation is given by:

y = mx + b

Where m is the slope of the equation, b is the y intercept, y is a dependent variable and x is the independent variable.

Let x represent the charge per megabyte used and let y represent the total charge for the month

since there is a $40 monthly fee and you are charged $4 per megabyte of data used, hence:

y = 4x + 40

Comparing with the standard linear equation:

The y intercept is 40, this means that even if no data is used, $40 must be paid.

The slope is 4, that is for every megabyte used, $4 is paid.

The amount to pay for 10 MB is:

y = 4(10) + 40 = $80

$80 is paid to use 10 megabytes

Find out more at: brainly.com/question/13911928

5 0

2 years ago

What is the sum of sqrt 18 plus sqrt 72

Tanzania [10]

18=2*3*3=2*3²
72=2*2*2*3*3=2³ *3²

√18+√72=√(2*3²) +√(2³ * 3²)=3√2 + 3*2√2=3√2 + 6√2=9√2

Answer: √18+√72=9√2

7 0

3 years ago

Help!!!! I have no idea how to even begin this

iris [78.8K]

Answer:

y=-7x+3

since the formula is y=mx+b where m is the slope and b is the y-intercept.

7 0

3 years ago

Read 2 more answers

Si un proyectil asciende verticalmente, y después de 3 segundos alcanza su altura máxima, calcule la velocidad que lleva a la mi

lys-0071 [83]

Answer:

The speed is 20.8 m/s

Step-by-step explanation:

If a projectile ascends vertically, and after 3 seconds it reaches its maximum height, calculate the velocity that it carries to the middle of its downward trajectory

Let the maximum height is h and initial velocity is u.

From first equation of motion

v = u + at

0 = u - g x 3

u = 3 g.....(1)

Use third equation of motion

$v^2 = u^2 - 2 gh \\\\0 = 9 g^2 - 2 gh \\\\h = 4.5 g$

Let the speed at half the height is v'.

$v^2 = u^2 + 2 gh \\\\v'^2 = 0 + 2 g\times 2.25 g\\\\v'^2 = 4.5\times 9.8\times9.8\\\\v' = 20.8 m/s$

8 0

3 years ago