Determine which of these illustrates two quantities that combine to make 0.

Mathematics

1 answer:

Butoxors [25]3 years ago

6 0

I think it’s gonna be D

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Please help, thanks if you do :)

Basile [38]

Your answer should be, 3x= 22y to the tenth power...

6 0

3 years ago

Ellie buys a mobile phone in spain for €352.50. Her brother jack buys an identical phone from japan for ¥39856. Using exchange r

Nonamiya [84]

Answer:

The answer to your question is: Japan

Step-by-step explanation:

Mobile cost in Spain = € 352.5

Mobile cost in Japan = ¥39856

Exchange rate = £1 = €1.41

£1 = ¥188

Cost of mobile in pounds

£ 1 ------------------ € 1.41

x ----------------- €352.5

x = (352.5 x 1) / 1.41

x= £250

£1 ------------------ ¥188

x ----------------- -¥ 39856

x = (39856 x 1) / 188

x = £212

Then, it was cheaper in Japan

8 0

3 years ago

Read 2 more answers

Dont leave any links please

Olin [163]

Answer:

m^2/n

Step-by-step explanation:

The following laws of exponent are useful to this problem:

$\displaystyle \large{ {(mn)}^{b} = {m}^{b} {n}^{b} } \\ \displaystyle \large{ {n}^{ - b} = \frac{1}{ {n}^{b} } }$

We are given the expression:

$\displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } }$

Use the first law of exponent above.

$\displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{(8)( \frac{1}{4}) } {n}^{ ( - 4)( \frac{1}{4}) } } \\ \displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{2 } {n}^{ - 1} }$

Make sure to recall the important necesscary fundamental math such as operation with negative numbers/integers, basic division, fraction, etc.

From the expression, apply the second law of exponent to n^-1.

$\displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{2 } ( \frac{1}{ {n}^{1} } )} \\ \displaystyle \large{( {m}^{8} {n}^{ - 4} )^{ \frac{1}{4} } = {m}^{2 } ( \frac{1}{ {n} } )} \\$