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Ilia_Sergeevich [38]
3 years ago
14

Determine which of these illustrates two quantities that combine to make 0.

Mathematics
1 answer:
Butoxors [25]3 years ago
6 0
I think it’s gonna be D
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Erin buys 4 packs of potatoes costing £2 each, 2 packs of carrots for £3 per pack, and 5 turnips costing 70p each.
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She would get £2.50

4 times 2 is 8
2 times 3 is 6
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It equals £2.50
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If the expression below has a positive value which inequality represents all possible values of X in the expression? -3x
prisoha [69]
-3x > 0
Divide both sides by -3 remembering to "flip" the inequality as you do so, because it's negative.
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3 years ago
rebecca wants to put 544 pennies in a coin collection book. the blue book fits 9 pennies per page. The red book fits 7 pennies p
ira [324]

Answer: 17 pages

Step-by-step explanation:well you would have to divide 544 by 9 to see hao many pages you would need for the blue book

544/9= 60.44 which would be 61

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3 years ago
Somebody help this assignment is due tonight for a grade
Law Incorporation [45]
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6 0
3 years ago
☆15 POINTS AND MARKED BRAINLIEST IF CORRECT☆<br>look at the image above to view the question!​
swat32

Answer:

3125 bacteria.

Step-by-step explanation:

We can write an exponential function to represent the situation.

We know that the current population is 100,000.

The population doubles each day.

The standard exponential function is given by:

P(t)=a(r)^t

Since our current population is 100,000, a = 100000.

Since our rate is doubling, r = 2.

So:

P(t)=100000(2)^t

We want to find the population five days ago.

So, we can say that t = -5. The negative represent the number of days that has passed.

Therefore:

\displaystyle P(-5)=100000(2)^{-5} = 100000 \Big( \frac{1}{32}\Big)  = 3125 \text{ bacteria}

However, we dealing within this context, we really can't have negative days. Although it works in this case, it can cause some confusion. So, let's write a function based on the original population.

We know that the bacterial population had been doubling for 5 days. Let A represent the initial population. So, our function is:

P(t)=A(2)^t

After 5 days, we reach the 100,000 population. So, when t = 5, P(t) = 100000:

100000=A(2)^5

And solving for A, we acquire:

\displaystyle A=\frac{100000}{2^5}=3125

So, our function in terms of the original day is:

P (t) = 3125 (2)^t

So, it becomes apparent that the initial population (or the population 5 days ago) is 3125 bacteria.

3 0
3 years ago
Read 2 more answers
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