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love history [14]
3 years ago
10

How to find the perimeter and area

Mathematics
1 answer:
Ad libitum [116K]3 years ago
3 0
For Perimeter you add all the sides of the figure and the total is your perimeter. For Area you multiply the length times the width.
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Find rhe volume of a cylinder with a diameter of 10 inches and a height of 20 inches
IrinaK [193]
Since the diameter of the cylinder is 10, its radius is half that, or 5, thus

\bf \textit{volume of a cylinder}\\\\
V=\pi r^2 h~~
\begin{cases}
r=radius\\
h=height\\
-----\\
r=5\\
h=20
\end{cases}\implies V=\pi (5)^2(20)
7 0
3 years ago
Please help!! I'll give brainliest! <br>Identifying Triangle Congruence​
ddd [48]

Answer:

1. SAS

2. SSS

3. ASA

4. AAS

5. RHS

7 0
3 years ago
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What is y over 3 (y/3) = 12
PSYCHO15rus [73]

Answer:

so what i would like to do is what is 12 divid by 3 and when u get ur answer that it what the y is

7 0
3 years ago
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Step by step!<br> I need to know how to do this because I’m pretty sure I’m doing this wrong.
AVprozaik [17]

Answer:

150

Step-by-step explanation:

The overall answer should equal 360. 90+90+30=210. That leaves us with x. Try subtracting 360-210=x. :) Hope this helps!

6 0
2 years ago
The table below represents the displacement of a horse from its barn as a function of time:
taurus [48]

"Part A: What is the y-intercept of the function, and what does this tell you about the horse? (4 points)" The y-intercept is (0,8), which tells us that at the beginning the horse is 8 miles from the barn.


"Part B: Calculate the average rate of change of the function represented by the table between x = 1 to x = 3 hours, and tell what the average rate represents. (4 points)" The value of the function at x=1 is 58 and that at x=3 is 158. Thus, the change in the horse's distance from the barn is 158-58, or 100 feet. The time period involved here is 2 sec. Thus, the average rate of change of the horse's position with respect to time is


100 feet

average rate of change = ---------------- = 50 ft/sec

2 sec


If the horse were to move steadily at a fixed rate from 58 feet to 158 feet from the barn, its average rate would be 50 ft/sec.


"Part C: What would be the domain of the function if the horse continued to walk at this rate until it traveled 508 feet from the barn? (2 points)"


Here time begins at x=0 and ends at x=4 sec. Thus, the appropriate domain here is [0,4] sec.


7 0
3 years ago
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