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AleksandrR [38]
3 years ago
8

What is 1+1 lol cool question hehe

Mathematics
1 answer:
Alex787 [66]3 years ago
7 0

Answer:

2

Step-by-step explanation:

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Answer : 7 or 7/1

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A circular sector has a central angle of π6 radians and a radius of 9 ft.
ohaa [14]

Answer:

\approx \: 21.2 \:  {ft}^{2}

Step-by-step explanation:

central \:  \angle   =  \frac{\pi ^{c} }{6}  = 30 \degree \\  \\ area \: of \: the \: sector =  \frac{30 \degree}{360 \degree}  \times \pi {(9)}^{2}  \\  \\  =  \frac{1}{12}  \times 3.14 \times  81 \\  \\  =   \frac{1}{12}  \times 254.34 \\  \\  = 21.195 \:  {ft}^{2}  \\  \\  \approx \: 21.2 \:  {ft}^{2}

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3 years ago
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Andrews [41]

Answer:

what the question

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Step-by-step explanation:

6 0
2 years ago
Cj your a goat for this lol HELP
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Answer:

>  

Step-by-step explanation:

brainliest please?

4 0
2 years ago
Suppose 52% of the population has a college degree. If a random sample of size 563563 is selected, what is the probability that
amm1812

Answer:

The value is  P(| \^ p -  p| < 0.05 ) = 0.9822

Step-by-step explanation:

From the question we are told that

    The population proportion is  p =  0.52

     The sample size is  n  =  563      

Generally the population mean of the sampling distribution is mathematically  represented as

           \mu_{x} =  p =  0.52

Generally the standard deviation of the sampling distribution is mathematically  evaluated as

       \sigma  =  \sqrt{\frac{ p(1- p)}{n} }

=>      \sigma  =  \sqrt{\frac{ 0.52 (1- 0.52 )}{563} }

=>      \sigma  =   0.02106

Generally the  probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as

            P(| \^ p -  p| < 0.05 ) =  P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 ))

  Here  \^ p is the sample proportion  of persons with a college degree.

So

 P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma }  < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )

Here  

    \frac{[\^p - p] - p}{\sigma }  = Z (The\ standardized \  value \  of\  (\^ p - p))

=> P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 )) = P[\frac{-0.47 - 0.52}{0.02106 }  <  Z  < \frac{-0.47 + 0.52}{0.02106 }]

=> P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 )) = P[ -2.37 <  Z  < 2.37 ]

=>  P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 )) = P(Z <  2.37 ) - P(Z < -2.37 )

From the z-table  the probability of  (Z <  2.37 ) and  (Z < -2.37 ) is

  P(Z <  2.37 ) = 0.9911

and

  P(Z <  - 2.37 ) = 0.0089

So

=>P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 )) =0.9911-0.0089

=>P( - (0.05 - 0.52 ) <  \^ p <  (0.05 + 0.52 )) = 0.9822

=> P(| \^ p -  p| < 0.05 ) = 0.9822

3 0
3 years ago
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