Given the equation :
We will use estimation to find the value of the given expression
So, the best estimation for the number 576 is = 600
The best estimation for the number 8 is = 10
So, the given expression is approximately = 600 ÷ 10 = 60
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We can calculate the error of the approximation as following :
The actual value is : 576 ÷ 8 = 72
So, the difference is = 72 - 60 = 12
so, the percentage of error will be :
Answer:
Both fireworks will explode after 1 seconds after firework b launches.
Step-by-step explanation:
Given:
Speed of fire work A= 300 ft/s
Speed of Firework B=240 ft/s
Time before which fire work b is launched =0.25s
To Find:
How many seconds after firework b launches will both fireworks explode=?
Solution:
Let t be the time(seconds) after which both the fireworks explode.
By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation
Firework A= 330(t)
Firework B=240(t)+240(0.25)
Since we need to know the same time after which they explode, we can equate both the equations
330(t) = 240(t)+240(0.25)
300(t)= 240(t)+60
300(t)-240(t)= 60
60(t)=60
t=1