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lana66690 [7]
3 years ago
6

Find (f/g)(x) for the following functions. f(x)= 18x3 - 7x2 + 5x-3; g(x)= -9x2 -2

Mathematics
2 answers:
lesantik [10]3 years ago
5 0

For this case we have the following functions:

f (x) = 18x ^3-7x^2 + 5x-3\\g (x) = - 9x ^ 2-2

We must find (\frac {f} {g}) (x). By definition we have to:

(\frac {f} {g}) (x) = \frac {f (x)} {g (x)}

So:

(\frac {f} {g}) (x) = \frac {18x ^ 3-7x ^ 2 + 5x-3} {- 9x ^ 2-2}

Where the denominator must be 0stint, so that the function is defined.

That is to say:

-9x ^ 2-2 other than 0.

ANswer:

(\frac {f} {g}) (x) = \frac {18x ^ 3-7x ^ 2 + 5x-3} {- 9x ^ 2-2}

With-9x ^ 2-2 other than 0

Verizon [17]3 years ago
4 0

Answer:

Step-by-step explanation: To find the function (f/g)(x) first we need to establish the limits as follows:

(f/g)(x)= \frac{18x3-7x2+5x-3}{-9x2-2}, ∀ x / -9x2-2≠0

-9x2-2=0  → 9x2=-2 → x2=-\frac{9}{2} → x=±√(9/2).

As we can see, the range of this function is ∀ x / x≠±√(9/2).

Becouse in those values, the function does´t have solution.

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