Ask question

Ask question

All categories

3 years ago

15

HELP I NEED ASSISTANCE

1 answer:

nalin [4]3 years ago

8 0

Okay, so first lets do the equation.

3/2(2+4b)
6/2 + 12/2b
3 + 6b

Now let us see if any of the equations in the box are equal to 3 + 6b.

Well we know that the first one is a no.

For the second on, 3(2b + 1), we get 6b + 3 which is equal to 3 + 6b.

The third one is not correct.

And of course the third one is correct.

So the answer is...

24b = no

3(2b+1) = yes

(6b + 2b) = no

6b + 3 = yes

You might be interested in

Write a inequality to represent a number is at most two

Arturiano [62]

Answer:

x≤2

Step-by-step explanation:

8 0

2 years ago

How do u estimate 5004

Brrunno [24]

Answer:

$5004 \approx5000$

3 0

2 years ago

Read 2 more answers

Can someone please help me with this?? please please please help me

Nadya [2.5K]

Step-by-step explanation:

base is 12, hypotenuse is 20

so X² is h²-b²

so X=16

8 0

2 years ago

Hey Bestie! 50 pts Pls help! Real answers only pls <3

frosja888 [35]

Answer:

$1. \: 3i$

2. option D

3. option C

4. option D

5. option C

6. option B

7. option C

8. option D

9. option C

10. option C

Step-by-step explanation:

<h2> $1. \: \sqrt{ - 9}$ </h2>

$\sqrt{ - 1(9)}$

$\sqrt{ - 1} \times \sqrt{ 9}$

$i \times \sqrt{9}$

$i \times \sqrt{ {3}^{2} }$

$i \times 3$

$3i$

<h2> $2. \: \sqrt{ - 8}$ </h2>

$\sqrt{ - 1(8)}$

$\sqrt{ - 1} \times \sqrt{8}$

$i \times \sqrt{8}$

$i \times \sqrt{ {2}^{2} \times 2 }$

$2i \sqrt{2}$

<h2> $3. \: \sqrt{ - 80}$ </h2>

$\sqrt{ - 1} \times \sqrt{80}$

$i \times \sqrt{80}$

$4i \: \sqrt{5}$

<h2> $4. \: \sqrt{ - 75}$ </h2>

$\sqrt{ - 1} \times \sqrt{75}$

$i \times \sqrt{75}$

$i \times \sqrt{ {5}^{2} \times 3 }$

$5i \sqrt{3}$

<h2> $5. \: \sqrt{ - 72}$ </h2>

$\sqrt{ - 1} \times \sqrt{72}$

$i \times \sqrt{72}$

$i \times ( {6}^{2} \times 2)$

$6i \sqrt{2}$

<h2> $6. \sqrt{ - 20}$ </h2>

$\sqrt{ - 1} \times \sqrt{20}$

$i \times \sqrt{20}$

$i \times \sqrt{ {2}^{2} \times 5}$

$2i \sqrt{5}$

<h2> $7. \: \sqrt{ - 27}$ </h2>

$\sqrt{ - 1} \times \sqrt{27}$

$i \times \sqrt{27}$

$i \times \sqrt{ {3}^{2} \times 3}$

$3i \sqrt{3}$

<h2> $8. \: \sqrt{ - 12}$ </h2>

$\sqrt{ - 1 \times 12}$

$i \times \sqrt{12}$

$i \times \sqrt{4(3)}$

$2i \sqrt{3}$

<h2> $9. \: \sqrt{ - 125}$ </h2>

$\sqrt{ - 1} \times \sqrt{125}$

$i \times \sqrt{ {5}^{2} \times 5 }$

$5i \sqrt{5}$

<h2> $10. \: \sqrt{ - 180}$ </h2>

$\sqrt{ - 1} \times \sqrt{180}$

$i \times \sqrt{ {6}^{2} \times 5 }$

$6i \sqrt{5}$

<h3>Hope it is helpful...</h3>

5 0

2 years ago

Ming weighed a bag of soil for a science experiment. The weight was 2.003 kg. She then removed 0.520 kg of soil from the bag. Ho

natima [27]

Just subtract 2.003 and 0.520 which gives you 1.483 so there is 1.483 kilogram of soil remaining hope this helps!

7 0

3 years ago

Read 2 more answers